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A two-dimensional array named Arr is with the range Arr[10........20, 25......45]. The base address of the array is 10 and the size of each element is 2 bytes. What will be the location of Arr[15][30] using column major order?
- a)35
- b)130
- c)230
- d)70
Correct answer is option 'B'. Can you explain this answer?
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A two-dimensional array named Arr is with the range Arr[10........20, ...
CONCEPT:
If the questions ask for Row major Order, then use the formula will be Address of A[I][J] = B + W * ((I – LR) * N + (J – LC)) where N will be the number of columns.
If the questions ask for Row major Order, then use the formula will be Address of A[I][J] = B + W * ((I – LR) * N + (J – LC)) where N will be the number of columns.
Column major order concept:
- Column major order means the element in a column is stored adjacent to each other. This basically works in a 2d and 3d array.
- Now we are given the base address along with the size of each element and the construction of a 2d array(row and column number )
- First, we have to calculate the no. of rows here = (Row upper limit - Row lower limit) + 1 = (20 - 10) + 1 = 11.
- We need no. of the column if the ques will ask about Row major order.
- There is a formula available to calculate it directly(Rather than going into deep how the formula came, it's better to remember the formula.)
FORMULA:-
Address of A[I][J] is can be calculated with the formula is A[I][J] = B + ((J – LC) * M + (I – LR))*W.
where;
Address of A[I][J] is can be calculated with the formula is A[I][J] = B + ((J – LC) * M + (I – LR))*W.
where;
- I- Row subset of an element whose address is to be found ( 15 here)
- J = Column Subset of an element whose address is to be found,(30 here)
- B- Base address(10 here)
- W- storage size of one element (2 bytes here)
- LR- the lower limit of row (u can take start index of the matrix)- (10 in this ques)
- LC-Lower limit of column(start column index of the matrix) - (25 in this ques)
- M- number of rows given in the matrix. (11 here)
Now solve the equation by solving the inner bracket first.
10+[5*11+5] *2 = 10+(60)*2 = 10+120 = 130 will be the answer.
10+[5*11+5] *2 = 10+(60)*2 = 10+120 = 130 will be the answer.
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A two-dimensional array named Arr is with the range Arr[10........20, 25......45]. The base address of the array is 10 and the size of each element is 2 bytes. What will be the location of Arr[15][30] using column major order?a)35b)130c)230d)70Correct answer is option 'B'. Can you explain this answer?
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