Which of the following is/are FALSE regarding pumping lemma for regular languages?a)Satisfying pumping lemma is a necessary condition for language to be regularb)Satisfying pumping lemma is a sufficient condition for language to be regularc)Not Satisfying pumping lemma is a necessary condition for language to be regulard)Not Satisfying pumping lemma is a sufficient condition for language to be not regularCorrect answer is option 'B,C'. Can you explain this answer?

Question

Answer

False Statements Regarding Pumping Lemma for Regular Languages:

b) Satisfying pumping lemma is a sufficient condition for a language to be regular.

The statement that satisfying the pumping lemma is a sufficient condition for a language to be regular is false. The pumping lemma is a necessary condition, but it is not sufficient. This means that if a language satisfies the pumping lemma, it may or may not be regular. The pumping lemma only guarantees that a language is not regular if it fails to satisfy the conditions of the lemma.

c) Not satisfying pumping lemma is a necessary condition for a language to be regular.

The statement that not satisfying the pumping lemma is a necessary condition for a language to be regular is also false. It is important to note that the pumping lemma can only be used to prove that a language is not regular. It cannot be used to prove that a language is regular. There are many regular languages that do not satisfy the pumping lemma, so the failure to satisfy the pumping lemma does not imply that a language is regular.

Explanation:

The pumping lemma for regular languages is a useful tool for proving that a language is not regular. It states that for any regular language L, there exists a constant p (the pumping length) such that any string s in L with length |s| ≥ p can be divided into three parts: s = xyz, satisfying the following conditions:

1. |xy| ≤ p: The length of xy (the first two parts of the string) is less than or equal to the pumping length.

2. |y| > 0: The length of y (the middle part of the string) is greater than zero.

3. For all i ≥ 0, the string xy^iz is also in L.

If a language fails to satisfy any of these conditions, it can be concluded that the language is not regular. However, it is important to note that satisfying the pumping lemma does not guarantee that a language is regular, as there are regular languages that do not satisfy the conditions of the pumping lemma.

In conclusion, the pumping lemma is a necessary condition for a language to be regular, but it is not sufficient. The failure to satisfy the pumping lemma does not necessarily imply that a language is regular. Therefore, options B and C are false statements regarding the pumping lemma for regular languages.

Answer

The pumping lemma is a necessary condition for language to be regular,
In other words, Not satisfying the pumping lemma is a sufficient condition for language to be not regular.
So statements 2 and 3 are false.

Similar Computer Science Engineering (CSE) Doubts

A language L satisfies the Pumping Lemma for regular languages, and also the Pumping Lemma for context-free languages. Which of the following statements about L is TRUE?

Let L1 be a recursive language. Let L2 and L3 be the languages that are recursively enumerable but not recursive. Which of the following statements is not necessarily true?

Which one of the following statements is TRUE?

Which of the following statements about regular languages is NOT true ?

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