A jar contains a mixture of two liquids A and B in the ratio 4 : 1. Wh...
Given
Jar contains a mixture of two liquids A and B in the ratio 4 : 1
Volume of liquid A =4x liters
Volume of liquid B= x liters
∴ Total volume of mixture = 4x + x = 5x liters
∴ 10 liter of the mixture is removed.
∴ Volume of liquid A removed =(4/5)x10 liters = 8 liters
Volume of liquid B removed = (1/5)x10 liters = 2 liters
Again, 10 liter of liquid B is added in place of 10 liters liquid
∴ Volume of liquid A in new mixture = (4x-8) liters
Volume of liquid B in new mixture =(x-2+10) liters = (x+8) liters
According to the question,
⇒3(4x - 8) = 2(x+8)
⇒12x - 24 = 2x + 16
⇒10x = 40
⇒x = 4
∴ Volume of A in earlier mixture = 4x4 liters = 16 liters
Hence, the volume of present in the jar earlier was 16 liters.