Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  #include <stdio.h>#if X == 3 #define Y... Start Learning for Free
#include <stdio.h>
#if X == 3
    #define Y 3
#else
    #define Y 5
#endif

int main()
{
    printf("%d", Y);
    return 0;
}
What is the output of the above program?
  • a)
    3
  • b)
    5
  • c)
    3 or 5 depending on value of X
  • d)
    Compile time error
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
#include <stdio.h>#if X == 3 #define Y 3#else #define Y 5#endi...
The output of the given program depends on the value of X.
However, in the given code, the value of X is not explicitly defined, so its value is undefined. If X is not defined or if its value is not explicitly set before the preprocessing phase, it is considered as 0 by default.
Since X is not defined, the #if X == 3 directive evaluates to false, and therefore, the else part of the #if directive is used, setting Y to 5.
So, the output of the program will be:
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Most Upvoted Answer
#include <stdio.h>#if X == 3 #define Y 3#else #define Y 5#endi...
I agree with the answer because in the abvoe program x is defined so x consists an garbage value or zero then if condition will flase because x==3 , nd else block will execute that is y=5.
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Community Answer
#include <stdio.h>#if X == 3 #define Y 3#else #define Y 5#endi...
The answer is b)5 because x value not given ,so if condition was failed and else block will be executed, so 5 will be printed
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#include <stdio.h>#if X == 3 #define Y 3#else #define Y 5#endifint main(){ printf("%d", Y); return 0;}What is the output of the above program?a)3b)5c)3 or 5 depending on value of Xd)Compile time errorCorrect answer is option 'B'. Can you explain this answer?
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