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Moment of inertia of a square of side 'b' about an axis through its centre of gravity is
- a)b3/3
- b)b4/3
- c)b4/12
- d)b4/8
Correct answer is option 'C'. Can you explain this answer?
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Moment of inertia of a square of side b about an axis through its cent...
Calculation of Moment of Inertia of a Square
Moment of inertia is the measure of resistance of a body to rotational motion. The moment of inertia of a square of side b about an axis through its centre of gravity can be calculated as follows:
- Consider a square of side b with its centre of gravity at the intersection of its diagonals.
- Divide the square into four equal parts by drawing two perpendicular lines passing through the centre of the square.
- Consider one of the parts of the square. Its moment of inertia about an axis passing through its centre of gravity and perpendicular to its plane can be calculated as I = (1/12)mb^2, where m is the mass of the part.
- The moment of inertia of the entire square about the same axis can be calculated as I = 4I = 4(1/12)mb^2 = (1/3)mb^2.
- Therefore, the moment of inertia of a square of side b about an axis passing through its centre of gravity and perpendicular to its plane is (1/3)mb^2.
The correct answer is option C, which provides the formula for the moment of inertia of a square of side b about an axis through its centre of gravity.
Moment of inertia is the measure of resistance of a body to rotational motion. The moment of inertia of a square of side b about an axis through its centre of gravity can be calculated as follows:
- Consider a square of side b with its centre of gravity at the intersection of its diagonals.
- Divide the square into four equal parts by drawing two perpendicular lines passing through the centre of the square.
- Consider one of the parts of the square. Its moment of inertia about an axis passing through its centre of gravity and perpendicular to its plane can be calculated as I = (1/12)mb^2, where m is the mass of the part.
- The moment of inertia of the entire square about the same axis can be calculated as I = 4I = 4(1/12)mb^2 = (1/3)mb^2.
- Therefore, the moment of inertia of a square of side b about an axis passing through its centre of gravity and perpendicular to its plane is (1/3)mb^2.
The correct answer is option C, which provides the formula for the moment of inertia of a square of side b about an axis through its centre of gravity.
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Moment of inertia of a square of side b about an axis through its cent...
Moment of inertia of an area or Second moment of area (MI):
- MI of a body about any axis is defined as the summation of the second moment of all elementary areas about the axis.
- I = Σ(A × d2)
Unit: m4 or mm4 or cm4
For a square of side a or b:
Moment of inertia is
For a square of side a or b:
Moment of inertia is
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Moment of inertia of a square of side b about an axis through its centre of gravity isa)b3/3b)b4/3c)b4/12d)b4/8Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Moment of inertia of a square of side b about an axis through its centre of gravity isa)b3/3b)b4/3c)b4/12d)b4/8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Moment of inertia of a square of side b about an axis through its centre of gravity isa)b3/3b)b4/3c)b4/12d)b4/8Correct answer is option 'C'. Can you explain this answer?.
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