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What is the mass MOI of right circular cone of radius R and height H about its axis?
  • a)
    4MR2/10
  • b)
    MR2/10
  • c)
    3MR2/10
  • d)
    MR2/12
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What is the mass MOI of right circular cone of radius R and height H a...
The mass MOI of right circular cone of radius R and height H about its axis is 3MR2/10.
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What is the mass MOI of right circular cone of radius R and height H a...
Understanding the Mass Moment of Inertia (MOI)
The mass moment of inertia (MOI) of an object quantifies its resistance to rotational motion about an axis. For a right circular cone with height H and radius R, we need to derive the MOI about its central axis.
Mass Distribution of a Cone
- A right circular cone can be visualized as a collection of infinitesimally thin discs stacked along its height.
- The mass (M) of the cone is uniformly distributed, and the volume (V) can be calculated as V = (1/3)πR²H.
Deriving the MOI for the Cone
1. Elemental Disc: Consider a thin disc at a height 'z' from the base with thickness 'dz'. Its radius can be expressed as (R/H)z.
2. Volume of the Disc: The volume of this elemental disc is dV = π[(R/H)z]²dz = (πR²z²/H²)dz.
3. Mass of the Disc: The mass of the elemental disc is dm = (M/V)dV = (3M/(πR²H))(πR²z²/H²)dz = (3Mz²/(H³))dz.
4. MOI Contribution: The contribution to the MOI from this disc is dI = (1/2)r²dm = (1/2)((R/H)z)²(3Mz²/(H³))dz.
5. Integrating: The total MOI I is found by integrating from z=0 to z=H.
6. Final Result: After performing the integration, we obtain I = (3/10)MR².
Conclusion
Thus, the mass moment of inertia of a right circular cone about its axis is:
- I = (3/10)MR²
The correct answer is option 'C' - 3MR²/10.
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