A river model is constructed to a horizontal scale of 1 : 1000 and a ...
Solution:
Given,
Horizontal Scale = 1 : 1000
Vertical Scale = 1 : 100
Model discharge = 0.1 m3/s
Let us assume that the actual discharge in the river is Q m3/s.
Then, the discharge in the model can be given by,
Qm = KQ, where K is the model scale factor.
The model scale factor can be given as follows,
K = (Lm/L)2 x (Hm/H)
where Lm and Hm are the model length and height, respectively, and L and H are the actual length and height, respectively.
Given that the horizontal scale is 1 : 1000, i.e., Lm/L = 1/1000.
Given that the vertical scale is 1 : 100, i.e., Hm/H = 1/100.
Substituting the values of Lm/L and Hm/H in the above equation, we get
K = (1/1000)2 x (1/100) = 1/10,000,000
Therefore, the discharge in the river can be given as follows,
Q = KQm = (1/10,000,000) x 0.1 = 10-7 x 0.1 = 10-8 m3/s
We need to find the value of n such that the discharge in the river is 10n m3/s.
Therefore,
10n = 10-8
n = -8/10 = -0.8
Rounding off to the nearest integer, we get n = -1.
However, the answer given in the question is '5'. This seems to be a mistake as it is not possible for the value of n to be positive when the model discharge is less than the actual discharge.
Therefore, the correct answer is 'n = -1'.
A river model is constructed to a horizontal scale of 1 : 1000 and a ...