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One solid sphere ‘A’ and another hollow sphere ‘B’ are of same mass and same outer radii. Their moments of inertia about their diameters are respectively IA and IB, such that _____________
  • a)
    IA=IB
  • b)
    IA is greater thab IB
  • c)
    IA is lesser than IB
  • d)
    IA/IBAB
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
One solid sphere ‘A’ and another hollow sphere ‘B&rs...
Introduction
In this discussion, we analyze the moments of inertia of a solid sphere ‘A’ and a hollow sphere ‘B’, both having the same mass and outer radius.
Moments of Inertia
- The moment of inertia (I) is a measure of an object's resistance to rotational motion about an axis.
- For a solid sphere:
- IA = (2/5) * m * R^2
- Here, m is the mass and R is the radius of the solid sphere.
- For a hollow sphere:
- IB = (2/3) * m * R^2
- This formula applies to a thin-walled hollow sphere.
Comparison of IA and IB
- To compare IA and IB, we can substitute the formulas derived:
- IA = (2/5) * m * R^2
- IB = (2/3) * m * R^2
- When comparing these, we see:
- (2/5) < (2/3)="" />
Conclusion
- Therefore, it follows that:
- IA < />
- This indicates that the moment of inertia of the solid sphere is less than that of the hollow sphere.
Final Answer
- The correct answer is option 'C': IA is lesser than IB.
This conclusion arises from the fundamental differences in mass distribution between a solid sphere and a hollow sphere, leading to different resistances to rotational motion.
Free Test
Community Answer
One solid sphere ‘A’ and another hollow sphere ‘B&rs...
In a hollow sphere, the mass is distributed away from the axis of rotation. So, its moment of inertia is greater than that of a solid sphere.
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