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A teacher gave a sum to his class to find the average of 'n' number wiz 1, 2, 3, ... n. But when the teacher checked the solution, he found that during calculation, a student just missed a number for addition and thus his average of 'n' numbers was 15. The least value of n is
  • a)
    n = 29
  • b)
    n = 30
  • c)
    n = 31
  • d)
    n = 32
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A teacher gave a sum to his class to find the average of 'n' number w...
Let the missing number be k.
The sum of series 1, 2, 3, …..n is n(n+1)/2
So, according to problem statement
n2 + n – 2k = 30n
n2 – 29n = 2k
n (n – 29) = 2k
So, at n ≤ 29, the above expression is invalid. Because at n ≤ 29, the value of k become either zero or negative.
So, least value of n is 30.
At n = 30, we have
30(30 – 29) = 2k
k = 15
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Community Answer
A teacher gave a sum to his class to find the average of 'n' number w...
The problem states that a teacher gave a sum to his class to find the average of 'n' numbers, starting from 1 to n. However, one student missed a number during the calculation, resulting in an average of 15 for the 'n' numbers. We need to determine the least value of 'n' that satisfies this condition.

To solve this problem, we can use the formula for the sum of an arithmetic series:

Sn = (n/2)(a + l)

Where Sn is the sum of the series, n is the number of terms, a is the first term, and l is the last term.

Let's break down the problem step by step:

1. Calculate the sum of the 'n' numbers without the missing term:

Sn = (n/2)(1 + n) - x

Where x is the missing term.

2. Calculate the sum of the 'n' numbers using the average:

Sn = 15n

3. Equate the two equations:

(n/2)(1 + n) - x = 15n

4. Simplify and rearrange the equation:

(n^2 + n)/2 - x = 15n

n^2 + n - 2x = 30n

n^2 - 29n + 2x = 0

5. Use the quadratic formula to solve for 'n':

n = (-b ± √(b^2 - 4ac))/(2a)

In this case, a = 1, b = -29, and c = 2x.

6. Since we are looking for the least value of 'n', we can consider only the positive root of the quadratic equation:

n = (-(-29) + √((-29)^2 - 4(1)(2x)))/(2(1))

n = (29 + √(841 - 8x))/2

7. The value of 'n' should be an integer, so we need to find the least value of 'x' that makes the expression inside the square root a perfect square.

8. By trial and error, we can determine that 'x' should be 6 to obtain a perfect square:

n = (29 + √(841 - 8(6)))/2

n = (29 + √(793))/2

n ≈ 29.82

9. Since 'n' should be an integer, the least value of 'n' that satisfies the condition is 30 (Option B).

Therefore, the correct answer is option 'B' - n = 30.
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A teacher gave a sum to his class to find the average of 'n' number wiz 1, 2, 3, ... n. But when the teacher checked the solution, he found that during calculation, a student just missed a number for addition and thus his average of 'n' numbers was 15. The least value of n isa)n = 29b)n = 30c)n = 31d)n = 32Correct answer is option 'B'. Can you explain this answer?
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A teacher gave a sum to his class to find the average of 'n' number wiz 1, 2, 3, ... n. But when the teacher checked the solution, he found that during calculation, a student just missed a number for addition and thus his average of 'n' numbers was 15. The least value of n isa)n = 29b)n = 30c)n = 31d)n = 32Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A teacher gave a sum to his class to find the average of 'n' number wiz 1, 2, 3, ... n. But when the teacher checked the solution, he found that during calculation, a student just missed a number for addition and thus his average of 'n' numbers was 15. The least value of n isa)n = 29b)n = 30c)n = 31d)n = 32Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A teacher gave a sum to his class to find the average of 'n' number wiz 1, 2, 3, ... n. But when the teacher checked the solution, he found that during calculation, a student just missed a number for addition and thus his average of 'n' numbers was 15. The least value of n isa)n = 29b)n = 30c)n = 31d)n = 32Correct answer is option 'B'. Can you explain this answer?.
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