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Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer?.

Solutions for Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Here you can find the meaning of Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer?, a detailed solution for Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? has been provided alongside types of Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Directions: In the figure shown, a steam power plant operates on a regenerative Rankine cycle and has a net power output of 150 MW. Steam enters the turbine at 10 MPa (h = 3375.1 kJ/kg) and the condenser at 10 kPa (hs = 2654.1 kJ/kg). The isentropic efficiency of the turbine is 80% and that of the pumps is 95% percent. Steam is extracted from the turbine at 0.5 MPa (hs = 2089.7 kJ/kg) to heat the feed-water in an open feed-water heater. Water leaves the feed-water heater as a saturated liquid. The thermodynamic states of water are given in the table.What will be the fraction of steam extracted from the turbine? (Answer up to two decimal places.)Correct answer is '0.17'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.