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Find the location of roots of characteristic equation and stability for closed loop system having characteristic equation as
S5+S4+4S3+4S2+4S+4=0
  • a)
    1pole in RHS of s plane 4 poles on imaginary axis ; unstable
  • b)
    2pole in RHS & 1 pole on LHS of s plane ,2 poles on imaginary axis ; unstable
  • c)
    1pole in RHS of s plane 4 poles on imaginary axis ; stable
  • d)
    1pole in LHS of s plane & multiple poles on imaginary axis ; unstable
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Find the location of roots of characteristic equation and stability f...
Of s plane, 3 poles on imaginary axis ; unstablec)3 poles in RHS of s plane, 2 poles on imaginary axis ; stabled)4 poles in RHS of s plane, 1 pole on imaginary axis ; stable
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Community Answer
Find the location of roots of characteristic equation and stability f...
R – H criteria
S3 row turns out to be zero
Forming auxiliary equation A (S) = 0 = S4 + 4S2 + 4
dA(s)/ds = 4S3 + 8S
Again S1 row turns out to be zero
Forming auxiliary equation & differentiating it we get S1 row term
A’1 (s) = 2S2 + 4
A’1 (s) = 4s
For frequency of oscillations
S4 + 4S2 + 4 = 0
(S2 + 2)2 = 0
S1, S2 = ±j2 =S3, S4
multiple roots on jw axis so system is unstable
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Find the location of roots of characteristic equation and stability for closed loop system having characteristic equation asS5+S4+4S3+4S2+4S+4=0a)1pole in RHS of s plane 4 poles on imaginary axis ; unstableb)2pole in RHS & 1 pole on LHS of s plane ,2 poles on imaginary axis ; unstablec)1pole in RHS of s plane 4 poles on imaginary axis ; stabled)1pole in LHS of s plane & multiple poles on imaginary axis ; unstableCorrect answer is option 'D'. Can you explain this answer?
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Find the location of roots of characteristic equation and stability for closed loop system having characteristic equation asS5+S4+4S3+4S2+4S+4=0a)1pole in RHS of s plane 4 poles on imaginary axis ; unstableb)2pole in RHS & 1 pole on LHS of s plane ,2 poles on imaginary axis ; unstablec)1pole in RHS of s plane 4 poles on imaginary axis ; stabled)1pole in LHS of s plane & multiple poles on imaginary axis ; unstableCorrect answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Find the location of roots of characteristic equation and stability for closed loop system having characteristic equation asS5+S4+4S3+4S2+4S+4=0a)1pole in RHS of s plane 4 poles on imaginary axis ; unstableb)2pole in RHS & 1 pole on LHS of s plane ,2 poles on imaginary axis ; unstablec)1pole in RHS of s plane 4 poles on imaginary axis ; stabled)1pole in LHS of s plane & multiple poles on imaginary axis ; unstableCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the location of roots of characteristic equation and stability for closed loop system having characteristic equation asS5+S4+4S3+4S2+4S+4=0a)1pole in RHS of s plane 4 poles on imaginary axis ; unstableb)2pole in RHS & 1 pole on LHS of s plane ,2 poles on imaginary axis ; unstablec)1pole in RHS of s plane 4 poles on imaginary axis ; stabled)1pole in LHS of s plane & multiple poles on imaginary axis ; unstableCorrect answer is option 'D'. Can you explain this answer?.
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