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If a bit string contains {0,1} only, having length 5 has no more than 2 ones in it. Then how many such bit strings are possible?
    Correct answer is '16'. Can you explain this answer?
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    If a bit string contains {0,1} only, having length 5 has no more than ...
    The total strings are 1(having no one in it) + 5 (having 1 one in it) + 10 (having 2 ones in it) = 16.
    The number of elements of the set of different binary strings of length 5 is 25 = 32. The I subset (strings 1 through 16) has a 0 as first bit and the II subset (strings 17 through 32) has an 1 as first bit.
    Hence, the correct answer is 16.
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    If a bit string contains {0,1} only, having length 5 has no more than ...
    Analysis:
    To solve this problem, we need to consider all possible ways to arrange 0s and 1s in a bit string of length 5, such that there are no more than 2 ones.

    Approach:
    We can approach this problem by considering the positions of the ones in the bit string.

    Case 1: 0 ones
    In this case, the bit string will consist of all 0s. There is only 1 way to arrange this, which is "00000".

    Case 2: 1 one
    There are 5 positions where the one can be placed in the bit string. Therefore, there are 5 ways to arrange this.

    Case 3: 2 ones
    There are 5 choose 2 = 10 ways to choose the positions for the two ones in the bit string. Therefore, there are 10 ways to arrange this.

    Total number of bit strings:
    Adding up the possibilities from all cases:
    1 (case 1) + 5 (case 2) + 10 (case 3) = 16
    Therefore, there are 16 possible bit strings of length 5 containing no more than 2 ones.
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    If a bit string contains {0,1} only, having length 5 has no more than 2 ones in it. Then how many such bit strings are possible?Correct answer is '16'. Can you explain this answer?
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