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Consider the grammar with non-terminals N = {S, C, S1) and terminals T = {a, b, i, t, e}, with S as the start symbol, and the following set of rules:
S → iCtSS1 | a
S1 → eS | ∈
C → b
The grammar is NOT LL(1) because
  • a)
    it is left recursive Correct Answer.
  • b)
    it is right recursive
  • c)
    it is ambiguous
  • d)
    it is not context-free
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Consider the grammar with non-terminals N = {S, C, S1) and terminals T...
The grammar has production:
S → iCtSS1
Here, the right hand side of the grammar has the same symbol as the left side. So, the grammar is left recursive and non-ambiguous.
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Community Answer
Consider the grammar with non-terminals N = {S, C, S1) and terminals T...

Explanation:

Left Recursion:
- Left recursion occurs when a non-terminal can directly derive itself as the leftmost symbol in a production rule. In this grammar, the production rule S→ iCtSS1 leads to left recursion because S appears as the leftmost symbol in the same rule.
- Left recursion can cause issues in LL(1) parsers as they cannot decide which production rule to choose based on the next input symbol, leading to conflicts.

Therefore, the grammar is NOT LL(1) due to left recursion.
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Consider the grammar with non-terminals N = {S, C, S1) and terminals T = {a, b, i, t, e}, with S as the start symbol, and the following set of rules:S→ iCtSS1 | aS1 →eS |∈C →bThe grammar is NOT LL(1) becausea)it is left recursive Correct Answer.b)it is right recursivec)it is ambiguousd)it is not context-freeCorrect answer is option 'A'. Can you explain this answer?
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Consider the grammar with non-terminals N = {S, C, S1) and terminals T = {a, b, i, t, e}, with S as the start symbol, and the following set of rules:S→ iCtSS1 | aS1 →eS |∈C →bThe grammar is NOT LL(1) becausea)it is left recursive Correct Answer.b)it is right recursivec)it is ambiguousd)it is not context-freeCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the grammar with non-terminals N = {S, C, S1) and terminals T = {a, b, i, t, e}, with S as the start symbol, and the following set of rules:S→ iCtSS1 | aS1 →eS |∈C →bThe grammar is NOT LL(1) becausea)it is left recursive Correct Answer.b)it is right recursivec)it is ambiguousd)it is not context-freeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the grammar with non-terminals N = {S, C, S1) and terminals T = {a, b, i, t, e}, with S as the start symbol, and the following set of rules:S→ iCtSS1 | aS1 →eS |∈C →bThe grammar is NOT LL(1) becausea)it is left recursive Correct Answer.b)it is right recursivec)it is ambiguousd)it is not context-freeCorrect answer is option 'A'. Can you explain this answer?.
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