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Which of the following CFG generates a language where the language is CFL but not regular?
- a)S → ABA → aA | bA | εB → aBb ∣ ε
- b)S → AaBA → aA | bA | εB → aB | bB | ε
- c)
S → ABA → aA ∣ εB → aBb | ε - d)None of these
Correct answer is option 'C'. Can you explain this answer?
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Which of the following CFG generates a language where the language is ...
A) S -> aSb | ε
This CFG generates a language where the language is CFL but not regular. The language generated by this CFG is "anbn" where n is the number of "a"s and "b"s are equal. This language is not regular because it cannot be recognized by a finite automaton.
This CFG generates a language where the language is CFL but not regular. The language generated by this CFG is "anbn" where n is the number of "a"s and "b"s are equal. This language is not regular because it cannot be recognized by a finite automaton.
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Which of the following CFG generates a language where the language is ...
In option (A) we have,
S → AB
A → aA | bA | ε
B → aBb ∣ ε
Here, L = (a + b) × a′bn = (a + b) is regular.
In option (B) we have,
S → AaB
A → aA | bA | ε
B → aB | bB | ε
Here, L= set of all strings which contain a as substring.
In option (C) we have,
S → AB
A → aA ∣ ε
B → aBb ∣ ε
Here, L= {ambn ∣ m > = n} is non regular but CFL.
Hence, the correct option is (C).
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Which of the following CFG generates a language where the language is CFL but not regular?a)S → ABA → aA | bA | εB → aBb εb)S → AaBA → aA | bA | εB → aB | bB | εc)S → ABA → aA εB → aBb | εd)None of theseCorrect answer is option 'C'. Can you explain this answer?
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