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A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.
The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,
Correct answer is '0.38'. Can you explain this answer?
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Most Upvoted Answer
A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upo...
Given,
specific gravity of oil = 0.8, Length of cylinder = 3 m
Net vertical force is given as follows,
Net vertical force = weight of water contained in semicircular volume RBP + Weight of oil contained in arc portion OQP of the cylinder.
Weight of water in semicircular volume RBP = Area of a semicircular arc × Length × Unit weight of water = 1/2 x π/4 × 22 × 3 × 9.81
= 46.23 kN
Weight of oil contained in arc portion OQP = Area of arc × Length × Unit weight of water = 1/4 x π/4 × 22 × 3 × (0.8 × 9.81)
= 18.49 kN
Net vertical force = 46.23 + 18.49 - Self weight = 64.72 kN - 25 kN = 39.72 kN
Net horizontal force:
Force due to water (FH,water) = 
= 9.81 × (1 + 1) × (2 × 3) = 117.72 kN
= 9.81 × (1 + 1) × (2 × 3) = 117.72 kNForce due to oil (FH,oil) = 
= (9.81 × 0.8) × 0.5 × (1 × 3) = 11.77 kN
= (9.81 × 0.8) × 0.5 × (1 × 3) = 11.77 kNNet horizontal force = 117.72 - 11.77 = 105.95 kN
Ratio = 
= 0.375
= 0.375Free Test
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Community Answer
A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upo...
Given,
specific gravity of oil = 0.8, Length of cylinder = 3 m
Net vertical force is given as follows,
Net vertical force = weight of water contained in semicircular volume RBP + Weight of oil contained in arc portion OQP of the cylinder.
Weight of water in semicircular volume RBP = Area of a semicircular arc × Length × Unit weight of water = 1/2 x π/4 × 22 × 3 × 9.81
= 46.23 kN
Weight of oil contained in arc portion OQP = Area of arc × Length × Unit weight of water = 1/4 x π/4 × 22 × 3 × (0.8 × 9.81)
= 18.49 kN
Net vertical force = 46.23 + 18.49 - Self weight = 64.72 kN - 25 kN = 39.72 kN
Net horizontal force:
Force due to water (FH,water) = = 9.81 × (1 + 1) × (2 × 3) = 117.72 kN
= 9.81 × (1 + 1) × (2 × 3) = 117.72 kNForce due to oil (FH,oil) = = (9.81 × 0.8) × 0.5 × (1 × 3) = 11.77 kN
= (9.81 × 0.8) × 0.5 × (1 × 3) = 11.77 kNNet horizontal force = 117.72 - 11.77 = 105.95 kN
Ratio = = 0.375
= 0.375Attention Civil Engineering (CE) Students!
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A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer?
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A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer?.
A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylinder (2.0 m diameter, 3.0 m long and 25 kN weight) is acted upon by water on one side and oil (specific gravity = 0.8) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (rounded off to two decimal places) is ______,Correct answer is '0.38'. Can you explain this answer?.
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