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Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:
Philosopher (int i)
{
while (1)
{
think ();
wait (lock);   ...(i)
wait (fork [i]);
wait (fork [(+1) % 5];
signal (lock);     ...(ii)
eat ();
wait (lock);      ...(iii)
signal (fork [i]);
signal (fork (i+1) % 5);
signal (lock);    .....(iv)
Which of the following is correct?
  • a)
     Removing (i) and (ii) will affect the code. The code will not work fine.
  • b)
     Removing (iii) and (iv) will not affect the code. The code still work fine.
  • c)
     Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.
  • d)
     All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.
Correct answer is option 'A,B'. Can you explain this answer?
Most Upvoted Answer
Consider the following proposed solution to the dining Philosophers pr...
Explanation:
The dining Philosophers problem is a classic synchronization problem in computer science where multiple processes or threads try to access a set of shared resources. In this problem, philosophers represent the processes or threads, and the forks represent the shared resources.

The proposed solution to avoid deadlock in the dining Philosophers problem includes the use of a binary semaphore lock and a set of forks. Let's analyze each part of the code to understand its purpose and whether it can be removed without affecting the functionality.

(i) wait(lock):
This line of code is used to acquire the lock before performing any actions. It ensures that only one philosopher can access the shared resources at a time. Removing this line of code would result in multiple philosophers trying to access the forks simultaneously, leading to a race condition and potential deadlock. Therefore, removing (i) would affect the code, and option 'A' is incorrect.

(ii) wait(fork[i]):
This line of code is used to acquire the fork on the left side of the philosopher. Philosophers need to acquire both forks before they can start eating. Removing this line of code would mean that philosophers can start eating without acquiring the required forks, leading to incorrect behavior. Therefore, removing (ii) would affect the code, and option 'A' is incorrect.

(iii) eat():
This line of code represents the eating action of the philosopher. Once the philosopher has acquired both forks, they can eat. Removing this line of code would result in philosophers acquiring the forks but never actually eating. Therefore, removing (iii) would affect the code, and option 'B' is incorrect.

(iv) signal(fork[i]) and signal(fork[(i+1) % 5]):
These lines of code release the acquired forks after the philosopher has finished eating. It allows other philosophers to acquire the forks and continue their actions. Removing these lines of code would result in forks being held indefinitely, causing deadlock. Therefore, removing (iv) would affect the code, and option 'B' is incorrect.

Conclusion:
Based on the analysis, the correct answer is option 'A, B'. Removing any of the mentioned lines of code would affect the functionality of the code and potentially lead to deadlock or incorrect behavior.
Free Test
Community Answer
Consider the following proposed solution to the dining Philosophers pr...
If, we remove the lock while acquiring the fork. It may lead to deadlock if all processes execute 9 statements before any philosopher has executed (ii) statement.
Removal of (iii) and (iv) will not affect the code, since no conflict can occur doing the V operation on forks.
Hence, the correct options are (A) and (B).
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Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:Philosopher (int i){while (1){think ();wait (lock); ...(i)wait (fork [i]);wait (fork [(+1) % 5];signal (lock); ...(ii)eat ();wait (lock); ...(iii)signal (fork [i]);signal (fork (i+1) % 5);signal (lock); .....(iv)Which of the following is correct?a)Removing (i) and (ii) will affect the code. The code will not work fine.b)Removing (iii) and (iv) will not affect the code. The code still work fine.c)Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.d)All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.Correct answer is option 'A,B'. Can you explain this answer?
Question Description
Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:Philosopher (int i){while (1){think ();wait (lock); ...(i)wait (fork [i]);wait (fork [(+1) % 5];signal (lock); ...(ii)eat ();wait (lock); ...(iii)signal (fork [i]);signal (fork (i+1) % 5);signal (lock); .....(iv)Which of the following is correct?a)Removing (i) and (ii) will affect the code. The code will not work fine.b)Removing (iii) and (iv) will not affect the code. The code still work fine.c)Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.d)All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.Correct answer is option 'A,B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:Philosopher (int i){while (1){think ();wait (lock); ...(i)wait (fork [i]);wait (fork [(+1) % 5];signal (lock); ...(ii)eat ();wait (lock); ...(iii)signal (fork [i]);signal (fork (i+1) % 5);signal (lock); .....(iv)Which of the following is correct?a)Removing (i) and (ii) will affect the code. The code will not work fine.b)Removing (iii) and (iv) will not affect the code. The code still work fine.c)Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.d)All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.Correct answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:Philosopher (int i){while (1){think ();wait (lock); ...(i)wait (fork [i]);wait (fork [(+1) % 5];signal (lock); ...(ii)eat ();wait (lock); ...(iii)signal (fork [i]);signal (fork (i+1) % 5);signal (lock); .....(iv)Which of the following is correct?a)Removing (i) and (ii) will affect the code. The code will not work fine.b)Removing (iii) and (iv) will not affect the code. The code still work fine.c)Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.d)All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.Correct answer is option 'A,B'. Can you explain this answer?.
Solutions for Consider the following proposed solution to the dining Philosophers problem to avoid deadlock. Consider the binary semaphore lock is initialized to 1:Philosopher (int i){while (1){think ();wait (lock); ...(i)wait (fork [i]);wait (fork [(+1) % 5];signal (lock); ...(ii)eat ();wait (lock); ...(iii)signal (fork [i]);signal (fork (i+1) % 5);signal (lock); .....(iv)Which of the following is correct?a)Removing (i) and (ii) will affect the code. The code will not work fine.b)Removing (iii) and (iv) will not affect the code. The code still work fine.c)Removing both 9, (ii), (iii) and (iv) will not affect the code. The code will still work fine.d)All (i), (ii), (iii) and (iv) are necessary. Removal of any of them will affect the code.Correct answer is option 'A,B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
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