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A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The speed of the first ball isa)20 m s−1b)10 m s−1c)5 m s−1d)15 m s−1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.