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A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.
The time interval between the throw of balls is
  • a)
    1.2 sec
  • b)
    0.5 sec
  • c)
    0.8 sec
  • d)
    1 sec
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A man is standing on top of a building 100 m high. He throws two ball...
Let the speeds of the two balls, 1 and 2, be v1 and v2, respectively. Since the speed of the second ball is half of the first, let
v1 = 2v ...(1)
v2 = v ...(2)
If y1 and y2 are the maximum heights reached by the balls 1 and 2, respectively, then
Since it is given that y1 − y2= 15 m
Substituting in equation
v1 = 20 m s−1
v2 = 10 m s−1
When maximum heights are reached,
Given that both the balls reach the maximum heights at the same time.
If t2 is the time taken by the ball 2 to cover a distance of 5 m, then from
Since t1 (time taken by ball 1 to cover distance of 20 m) is 2 s, time interval between the two throws,
= t1 − t2 = 2 − 1 = 1 s
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A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The time interval between the throw of balls isa)1.2 secb)0.5 secc)0.8 secd)1 secCorrect answer is option 'D'. Can you explain this answer?
Question Description
A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The time interval between the throw of balls isa)1.2 secb)0.5 secc)0.8 secd)1 secCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The time interval between the throw of balls isa)1.2 secb)0.5 secc)0.8 secd)1 secCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and after a time interval (less than 22 seconds). The later ball is thrown at a velocity of half the first. At t = 2 s, both the balls reach their maximum heights. At this time the vertical gap between first and second ball is +15m.The time interval between the throw of balls isa)1.2 secb)0.5 secc)0.8 secd)1 secCorrect answer is option 'D'. Can you explain this answer?.
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