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To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?
  • a)
    0.155
  • b)
    0.167
  • c)
    0.195
  • d)
    0.213
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
To provide safety against piping failure, with a factor of safety of ...
Exit gradient = seepage pressure per unit volume
Critical ic = when n = 0.35
= (G - 1)(1 - n)
= (2.5 - 1)(1 - 0.35) = 0.975
Maximum possible exit gradient with factor of safety
of 5 = 0.975/5 = 0.195
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To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?a)0.155b)0.167c)0.195d)0.213Correct answer is option 'C'. Can you explain this answer?
Question Description
To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?a)0.155b)0.167c)0.195d)0.213Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?a)0.155b)0.167c)0.195d)0.213Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To provide safety against piping failure, with a factor of safety of 5, what should be the maximum permissible exit gradient for soil with a specific gravity of 2.5 and porosity of 0.35?a)0.155b)0.167c)0.195d)0.213Correct answer is option 'C'. Can you explain this answer?.
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