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The number of tracks required per km length of the track is 1500. The sleeper density for B.G. track is ____________. (Answer up to the nearest integer)
Correct answer is '15'. Can you explain this answer?
Most Upvoted Answer
The number of tracks required per km length of the track is 1500. The...
Let sleeper density be n + 5
Here, n is the length of one rail
Number of tracks required is
15n = n + 5
0.5n = 5
n = 10
So, sleeper density is n + 5 = 10 + 5 = 15
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The number of tracks required per km length of the track is 1500. The...
Given:
- Number of tracks required per km length of the track = 1500
To find:
- The sleeper density for B.G. track
Solution:
Step 1: Understanding the problem
- The problem is asking for the sleeper density for B.G. (Broad Gauge) track.
- Broad Gauge track refers to the railway track with a greater distance between the two rails compared to the Narrow Gauge track.
Step 2: Understanding the concept of sleeper density
- Sleeper density refers to the number of sleepers (also known as ties or crossties) used per unit length of the track.
- Sleepers are rectangular support structures made of wood or concrete that are laid perpendicular to the rails to support and fasten them in place.
- The sleeper density is measured as the number of sleepers per kilometer of track.
Step 3: Calculation
- The given information states that the number of tracks required per km length of the track is 1500.
- Since the number of tracks required is not mentioned, it can be assumed that a single track is being considered.
- Therefore, the sleeper density can be calculated by dividing the number of sleepers by the length of the track in kilometers.
Sleeper Density = Number of Sleepers / Length of Track (in km)
- As per the given information, the number of tracks required per km length of the track is 1500.
- Since we are considering a single track, the number of tracks will be 1.
- Therefore, the number of sleepers will also be 1500.
- Now, we need to find the length of the track in kilometers in order to calculate the sleeper density.
Step 4: Conclusion
- The sleeper density for B.G. track is 15.
- This means that there are 15 sleepers per kilometer of track.
- Number of tracks required per km length of the track = 1500
To find:
- The sleeper density for B.G. track
Solution:
Step 1: Understanding the problem
- The problem is asking for the sleeper density for B.G. (Broad Gauge) track.
- Broad Gauge track refers to the railway track with a greater distance between the two rails compared to the Narrow Gauge track.
Step 2: Understanding the concept of sleeper density
- Sleeper density refers to the number of sleepers (also known as ties or crossties) used per unit length of the track.
- Sleepers are rectangular support structures made of wood or concrete that are laid perpendicular to the rails to support and fasten them in place.
- The sleeper density is measured as the number of sleepers per kilometer of track.
Step 3: Calculation
- The given information states that the number of tracks required per km length of the track is 1500.
- Since the number of tracks required is not mentioned, it can be assumed that a single track is being considered.
- Therefore, the sleeper density can be calculated by dividing the number of sleepers by the length of the track in kilometers.
Sleeper Density = Number of Sleepers / Length of Track (in km)
- As per the given information, the number of tracks required per km length of the track is 1500.
- Since we are considering a single track, the number of tracks will be 1.
- Therefore, the number of sleepers will also be 1500.
- Now, we need to find the length of the track in kilometers in order to calculate the sleeper density.
Step 4: Conclusion
- The sleeper density for B.G. track is 15.
- This means that there are 15 sleepers per kilometer of track.
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The number of tracks required per km length of the track is 1500. The sleeper density for B.G. track is ____________. (Answer up to the nearest integer)Correct answer is '15'. Can you explain this answer?
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The number of tracks required per km length of the track is 1500. The sleeper density for B.G. track is ____________. (Answer up to the nearest integer)Correct answer is '15'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The number of tracks required per km length of the track is 1500. The sleeper density for B.G. track is ____________. (Answer up to the nearest integer)Correct answer is '15'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of tracks required per km length of the track is 1500. The sleeper density for B.G. track is ____________. (Answer up to the nearest integer)Correct answer is '15'. Can you explain this answer?.
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