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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)
Correct answer is '313'. Can you explain this answer?
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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of ...
CO2 and CH4 are the green house gases.
Production of MSW per capita
120g MSW produce (50 + 25) = 75 g green house gas
500 g MSW will produce
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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of ...
Given Information:
- Mass of CO2 produced from the decomposition of MSW = 50 g
- Mass of CH4 produced from the decomposition of MSW = 25 g
- Formula weight of MSW = 120 g
- City population = 1 million people
- MSW production rate = 500 ton/day
Calculations:
1. Calculate the total mass of MSW produced per day:
Mass of MSW produced per day = MSW production rate = 500 ton/day
2. Calculate the total mass of MSW produced by the city's population per day:
Mass of MSW produced per day = MSW production rate × population
Mass of MSW produced per day = 500 ton/day × 1 million = 500,000 ton/day
3. Convert the mass of MSW produced per day to grams:
Mass of MSW produced per day = 500,000 ton/day × 1000 kg/ton × 1000 g/kg = 5 × 10^11 g/day
4. Calculate the molar mass of MSW:
Molar mass of MSW = Formula weight of MSW = 120 g/mol
5. Calculate the number of moles of MSW produced per day:
Number of moles of MSW = Mass of MSW produced per day / Molar mass of MSW
Number of moles of MSW = 5 × 10^11 g/day / 120 g/mol = 4.17 × 10^9 mol/day
6. Calculate the number of moles of CO2 produced per day:
Number of moles of CO2 = Mass of CO2 produced / Molar mass of CO2
Number of moles of CO2 = 50 g / 44 g/mol = 1.14 mol
7. Calculate the number of moles of CH4 produced per day:
Number of moles of CH4 = Mass of CH4 produced / Molar mass of CH4
Number of moles of CH4 = 25 g / 16 g/mol = 1.56 mol
8. Calculate the total number of moles of greenhouse gases produced per day:
Total number of moles of greenhouse gases = Number of moles of CO2 + Number of moles of CH4
Total number of moles of greenhouse gases = 1.14 mol + 1.56 mol = 2.7 mol
9. Calculate the average per capita greenhouse gas production per day:
Average per capita greenhouse gas production = Total number of moles of greenhouse gases / population
Average per capita greenhouse gas production = 2.7 mol / 1 million = 2.7 × 10^(-6) mol/person
10. Convert the average per capita greenhouse gas production to grams per day:
Average per capita greenhouse gas production = Average per capita greenhouse gas production × Molar mass of greenhouse gases
Average per capita greenhouse gas production = 2.7 × 10^(-6) mol/person × (44 g/mol + 16 g/mol) = 2.7 × 10^(-6) mol/person × 60 g/mol = 1.62 × 10^(-4) g/person
11. Convert the average per capita greenhouse gas production to grams per
- Mass of CO2 produced from the decomposition of MSW = 50 g
- Mass of CH4 produced from the decomposition of MSW = 25 g
- Formula weight of MSW = 120 g
- City population = 1 million people
- MSW production rate = 500 ton/day
Calculations:
1. Calculate the total mass of MSW produced per day:
Mass of MSW produced per day = MSW production rate = 500 ton/day
2. Calculate the total mass of MSW produced by the city's population per day:
Mass of MSW produced per day = MSW production rate × population
Mass of MSW produced per day = 500 ton/day × 1 million = 500,000 ton/day
3. Convert the mass of MSW produced per day to grams:
Mass of MSW produced per day = 500,000 ton/day × 1000 kg/ton × 1000 g/kg = 5 × 10^11 g/day
4. Calculate the molar mass of MSW:
Molar mass of MSW = Formula weight of MSW = 120 g/mol
5. Calculate the number of moles of MSW produced per day:
Number of moles of MSW = Mass of MSW produced per day / Molar mass of MSW
Number of moles of MSW = 5 × 10^11 g/day / 120 g/mol = 4.17 × 10^9 mol/day
6. Calculate the number of moles of CO2 produced per day:
Number of moles of CO2 = Mass of CO2 produced / Molar mass of CO2
Number of moles of CO2 = 50 g / 44 g/mol = 1.14 mol
7. Calculate the number of moles of CH4 produced per day:
Number of moles of CH4 = Mass of CH4 produced / Molar mass of CH4
Number of moles of CH4 = 25 g / 16 g/mol = 1.56 mol
8. Calculate the total number of moles of greenhouse gases produced per day:
Total number of moles of greenhouse gases = Number of moles of CO2 + Number of moles of CH4
Total number of moles of greenhouse gases = 1.14 mol + 1.56 mol = 2.7 mol
9. Calculate the average per capita greenhouse gas production per day:
Average per capita greenhouse gas production = Total number of moles of greenhouse gases / population
Average per capita greenhouse gas production = 2.7 mol / 1 million = 2.7 × 10^(-6) mol/person
10. Convert the average per capita greenhouse gas production to grams per day:
Average per capita greenhouse gas production = Average per capita greenhouse gas production × Molar mass of greenhouse gases
Average per capita greenhouse gas production = 2.7 × 10^(-6) mol/person × (44 g/mol + 16 g/mol) = 2.7 × 10^(-6) mol/person × 60 g/mol = 1.62 × 10^(-4) g/person
11. Convert the average per capita greenhouse gas production to grams per
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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer?
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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer?.
If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer?.
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If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer?, a detailed solution for If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? has been provided alongside types of If 50 g of CO2 and 25 g of CH4 are produced from the decomposition of municipal solid waste (MSW) with a formula weight of 120 g, then what is the average per capita greenhouse gas production (in g/day) in a city of 1 million people with a MSW production rate of 500 ton/day? (Answer up to the nearest integer)Correct answer is '313'. Can you explain this answer? theory, EduRev gives you an
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