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Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.
C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2
The methane production of the decomposable material is governed by the following stoichiometric relation
CaHbOcNd + nH2O → mCH4 + sCO2 + dNH3
Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______
Correct answer is '137.6'. Can you explain this answer?
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Raw municipal solid waste (MSW) collected from a city contains 70% dec...
For the MSW, the phase diagram is as follows
From the mass percent given,
12a = 44x
b = 6x 16c = 43x
14d = 0.8x
∑ = 100x
100x = wt of decomposable waste
= 0.455 kg
⇒ a = 16.683, b = 27.3,
c = 12.228, d = 0.26
From the balance of reaction we have
a = m + s …(A)
b + 2n = 4m + 3d …(B)
c + n = 2s …(C)
⇒ 2c + 2n = 4s …(D)
⇒ b – 2c = 4m – 4s + 3d
⇒ m - s = 0.516
⇒ m + s = 16.683
⇒ m = 8.6
⇒ Methane produced = 8.6 × 16 g = 137.6 g
Most Upvoted Answer
Raw municipal solid waste (MSW) collected from a city contains 70% dec...
The stoichiometric relation for methane production from the decomposable material can be written as follows:
C44H6O43N0.8 + (106/18)H2O → 44CH4 + 43CO2 + 0.8NH3
This equation shows that for every mole of decomposable material, 44 moles of methane are produced along with 43 moles of carbon dioxide and 0.8 moles of ammonia. The water required for the reaction is calculated based on the assumption that the water content of the decomposable material is 35%.
To calculate the methane production from a given amount of MSW, we need to know the amount of decomposable material in the MSW. Let's assume that the MSW contains 1000 kg of material, of which 70% is decomposable.
Amount of decomposable material = 0.7 x 1000 kg = 700 kg
The elemental analysis of the decomposable material tells us that it contains 44% carbon, 6% hydrogen, 43% oxygen, 0.8% nitrogen, and 6.2% other elements. To calculate the amount of each element in 1 kg of decomposable material, we can use the mass percentages and the molar masses of the elements:
Amount of C = (44/12) x 1 kg = 3.67 moles
Amount of H = (6/1) x 1 kg = 6 moles
Amount of O = (43/16) x 1 kg = 2.69 moles
Amount of N = (0.8/14) x 1 kg = 0.057 moles
Amount of other = (6.2/100) x 1 kg = 0.062 moles
The stoichiometric relation tells us that 1 mole of decomposable material produces 44 moles of methane. Therefore, the 700 kg of decomposable material in the MSW can produce:
Methane production = 44 x 700 = 30800 moles
To convert this to mass, we need to multiply by the molar mass of methane:
Methane production = 44 x 700 x 16 = 8.84 tonnes
Therefore, the 1000 kg of MSW can produce 8.84 tonnes of methane through anaerobic digestion of the decomposable material. Note that this calculation does not take into account the non-decomposable materials in the MSW, which will not contribute to methane production.
C44H6O43N0.8 + (106/18)H2O → 44CH4 + 43CO2 + 0.8NH3
This equation shows that for every mole of decomposable material, 44 moles of methane are produced along with 43 moles of carbon dioxide and 0.8 moles of ammonia. The water required for the reaction is calculated based on the assumption that the water content of the decomposable material is 35%.
To calculate the methane production from a given amount of MSW, we need to know the amount of decomposable material in the MSW. Let's assume that the MSW contains 1000 kg of material, of which 70% is decomposable.
Amount of decomposable material = 0.7 x 1000 kg = 700 kg
The elemental analysis of the decomposable material tells us that it contains 44% carbon, 6% hydrogen, 43% oxygen, 0.8% nitrogen, and 6.2% other elements. To calculate the amount of each element in 1 kg of decomposable material, we can use the mass percentages and the molar masses of the elements:
Amount of C = (44/12) x 1 kg = 3.67 moles
Amount of H = (6/1) x 1 kg = 6 moles
Amount of O = (43/16) x 1 kg = 2.69 moles
Amount of N = (0.8/14) x 1 kg = 0.057 moles
Amount of other = (6.2/100) x 1 kg = 0.062 moles
The stoichiometric relation tells us that 1 mole of decomposable material produces 44 moles of methane. Therefore, the 700 kg of decomposable material in the MSW can produce:
Methane production = 44 x 700 = 30800 moles
To convert this to mass, we need to multiply by the molar mass of methane:
Methane production = 44 x 700 x 16 = 8.84 tonnes
Therefore, the 1000 kg of MSW can produce 8.84 tonnes of methane through anaerobic digestion of the decomposable material. Note that this calculation does not take into account the non-decomposable materials in the MSW, which will not contribute to methane production.
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Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer?
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Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer?.
Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer?.
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Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer?, a detailed solution for Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? has been provided alongside types of Raw municipal solid waste (MSW) collected from a city contains 70% decomposable material that can be converted to methane. The water content of the decomposable material is 35%. An elemental anlysis of the decomposable material yields the following mass percent.C : H : O: N : other = 44 : 6 : 43 : 0.8 : 6.2The methane production of the decomposable material is governed by the following stoichiometric relationCaHbOcNd + nH2O → mCH4 + sCO2 + dNH3Given atomic weights: C = 12, H = 1, O = 16, N = The mass of methane produced (in grams, round off to 1 decimal place) per kg of raw MSW will be _______Correct answer is '137.6'. Can you explain this answer? theory, EduRev gives you an
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