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At a municipal waste handling facility, 30 metric ton mixture of food waste, yard waste, and paper waste was available. The moisture content of this mixture was found to be 10%. The ideal moisture content for composting this mixture is 50%, The amount of water to be added to this mixture to bring its moisture content to the ideal condition is______ metric ton, (in integer)
Correct answer is '24'. Can you explain this answer?
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At a municipal waste handling facility, 30 metric ton mixture of food ...
Given information:
- Total weight of waste mixture = 30 metric tons
- Moisture content of the mixture = 10%
- Ideal moisture content for composting = 50%
To find:
- The amount of water to be added to bring the moisture content to the ideal condition
Approach:
1. Calculate the initial moisture content in the waste mixture.
2. Calculate the dry weight of the waste mixture.
3. Determine the amount of water required to achieve the ideal moisture content.
4. Convert the amount of water required to metric tons.
Calculation:
Step 1: Calculate initial moisture content
Initial moisture content = (Weight of water / Total weight of waste mixture) * 100
Given that the initial moisture content is 10% and the total weight of the waste mixture is 30 metric tons, we can calculate the weight of water.
Weight of water = (10/100) * 30 metric tons = 3 metric tons
Step 2: Calculate dry weight of waste mixture
Dry weight = Total weight of waste mixture - Weight of water
Dry weight = 30 metric tons - 3 metric tons = 27 metric tons
Step 3: Determine amount of water required to achieve ideal moisture content
Ideal moisture content = (Weight of water / Total weight of waste mixture) * 100
Given that the ideal moisture content is 50% and the total weight of the waste mixture is 30 metric tons, we can calculate the weight of water required.
Weight of water required = (50/100) * 30 metric tons = 15 metric tons
Step 4: Convert amount of water required to metric tons
Amount of water required = Weight of water required - Weight of water already present
Amount of water required = 15 metric tons - 3 metric tons = 12 metric tons
Answer:
The amount of water to be added to bring the moisture content to the ideal condition is 12 metric tons.
- Total weight of waste mixture = 30 metric tons
- Moisture content of the mixture = 10%
- Ideal moisture content for composting = 50%
To find:
- The amount of water to be added to bring the moisture content to the ideal condition
Approach:
1. Calculate the initial moisture content in the waste mixture.
2. Calculate the dry weight of the waste mixture.
3. Determine the amount of water required to achieve the ideal moisture content.
4. Convert the amount of water required to metric tons.
Calculation:
Step 1: Calculate initial moisture content
Initial moisture content = (Weight of water / Total weight of waste mixture) * 100
Given that the initial moisture content is 10% and the total weight of the waste mixture is 30 metric tons, we can calculate the weight of water.
Weight of water = (10/100) * 30 metric tons = 3 metric tons
Step 2: Calculate dry weight of waste mixture
Dry weight = Total weight of waste mixture - Weight of water
Dry weight = 30 metric tons - 3 metric tons = 27 metric tons
Step 3: Determine amount of water required to achieve ideal moisture content
Ideal moisture content = (Weight of water / Total weight of waste mixture) * 100
Given that the ideal moisture content is 50% and the total weight of the waste mixture is 30 metric tons, we can calculate the weight of water required.
Weight of water required = (50/100) * 30 metric tons = 15 metric tons
Step 4: Convert amount of water required to metric tons
Amount of water required = Weight of water required - Weight of water already present
Amount of water required = 15 metric tons - 3 metric tons = 12 metric tons
Answer:
The amount of water to be added to bring the moisture content to the ideal condition is 12 metric tons.
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Community Answer
At a municipal waste handling facility, 30 metric ton mixture of food ...
Total municipal waste = 30 MT
∴ Moisture content (given) = 10% i.e. 3 MT
∴ Solid mass = 30 - 0.1(30) = 27 MT
Ideally moisture content of mix = 50% (given)
Total mass of waste ideally must be = (T) = 27 + 0.5 (T)
∴ Total mass = 54 MT (in which 27 MT is water) = 54 MT
Amount of water added = 27 - 3 = 24 MT
(∴ 3 MT water is already added)
∴ Moisture content (given) = 10% i.e. 3 MT
∴ Solid mass = 30 - 0.1(30) = 27 MT
Ideally moisture content of mix = 50% (given)
Total mass of waste ideally must be = (T) = 27 + 0.5 (T)
∴ Total mass = 54 MT (in which 27 MT is water) = 54 MT
Amount of water added = 27 - 3 = 24 MT
(∴ 3 MT water is already added)
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At a municipal waste handling facility, 30 metric ton mixture of food waste, yard waste, and paper waste was available. The moisture content of this mixture was found to be 10%. The ideal moisture content for composting this mixture is 50%, The amount of water to be added to this mixture to bring its moisture content to the ideal condition is______ metric ton, (in integer)Correct answer is '24'. Can you explain this answer?
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