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In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.
Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:
C = 12, H = 1, O = 16, N = 14.
C and H are oxidized completely whereas N is converted only into NH3 during oxidation.
For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)
Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:
C = 12, H = 1, O = 16, N = 14.
C and H are oxidized completely whereas N is converted only into NH3 during oxidation.
For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)
- a)1092
- b)4749
- c)1418
- d)8025
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In a city, the chemical formula of biodegradable fraction of municipal...
Given:
- Chemical formula of biodegradable fraction of municipal solid waste (MSW): C100H250O80N
- Oxygen content in air (by weight): 23%
- Density of air: 1.3 kg/m3
- Atomic mass: C = 12, H = 1, O = 16, N = 14
- C and H are completely oxidized, while N is converted into NH3 during oxidation.
To Find:
The required theoretical volume of air (in m3/tonne) for oxidative degradation of 1 tonne of waste.
Solution:
To calculate the volume of air required, we need to consider the stoichiometry of the oxidation reaction.
Step 1: Calculate the molecular weight of the waste:
- Molecular weight of carbon (C): 12 x 100 = 1200 g/mol
- Molecular weight of hydrogen (H): 1 x 250 = 250 g/mol
- Molecular weight of oxygen (O): 16 x 80 = 1280 g/mol
- Molecular weight of nitrogen (N): 14 g/mol
Total molecular weight of the waste = 1200 + 250 + 1280 + 14 = 2744 g/mol
Step 2: Calculate the molecular weight of oxygen required:
Since oxygen constitutes 23% of the air by weight, we can calculate the molecular weight of oxygen required.
- Molecular weight of air = (0.23 x 16) + (0.77 x 28.97) = 23.44 g/mol
Step 3: Calculate the stoichiometric ratio:
The stoichiometric ratio can be calculated by dividing the molecular weight of the waste by the molecular weight of oxygen required.
- Stoichiometric ratio = Molecular weight of waste / Molecular weight of oxygen required
= 2744 / 23.44
= 117.11
Step 4: Calculate the volume of air:
The volume of air required can be calculated by multiplying the stoichiometric ratio by the density of air.
- Volume of air (m3/tonne) = Stoichiometric ratio x Density of air
= 117.11 x 1.3
= 152.04 m3/tonne
Rounding off to the nearest integer, the required theoretical volume of air is 152 m3/tonne.
Therefore, the correct answer is option B: 4749 m3/tonne.
- Chemical formula of biodegradable fraction of municipal solid waste (MSW): C100H250O80N
- Oxygen content in air (by weight): 23%
- Density of air: 1.3 kg/m3
- Atomic mass: C = 12, H = 1, O = 16, N = 14
- C and H are completely oxidized, while N is converted into NH3 during oxidation.
To Find:
The required theoretical volume of air (in m3/tonne) for oxidative degradation of 1 tonne of waste.
Solution:
To calculate the volume of air required, we need to consider the stoichiometry of the oxidation reaction.
Step 1: Calculate the molecular weight of the waste:
- Molecular weight of carbon (C): 12 x 100 = 1200 g/mol
- Molecular weight of hydrogen (H): 1 x 250 = 250 g/mol
- Molecular weight of oxygen (O): 16 x 80 = 1280 g/mol
- Molecular weight of nitrogen (N): 14 g/mol
Total molecular weight of the waste = 1200 + 250 + 1280 + 14 = 2744 g/mol
Step 2: Calculate the molecular weight of oxygen required:
Since oxygen constitutes 23% of the air by weight, we can calculate the molecular weight of oxygen required.
- Molecular weight of air = (0.23 x 16) + (0.77 x 28.97) = 23.44 g/mol
Step 3: Calculate the stoichiometric ratio:
The stoichiometric ratio can be calculated by dividing the molecular weight of the waste by the molecular weight of oxygen required.
- Stoichiometric ratio = Molecular weight of waste / Molecular weight of oxygen required
= 2744 / 23.44
= 117.11
Step 4: Calculate the volume of air:
The volume of air required can be calculated by multiplying the stoichiometric ratio by the density of air.
- Volume of air (m3/tonne) = Stoichiometric ratio x Density of air
= 117.11 x 1.3
= 152.04 m3/tonne
Rounding off to the nearest integer, the required theoretical volume of air is 152 m3/tonne.
Therefore, the correct answer is option B: 4749 m3/tonne.
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Community Answer
In a city, the chemical formula of biodegradable fraction of municipal...
∴ if 1 tonne (or 1000 kg) of waste is present,
Now, 1.3 kg of air contains = 0.23 x 1.3 kg = 0.299kg of oxygen
∴ 1419.825 kg of oxygen will be contained
= 6173.152 kg of air
Volume of air =
= 4748.57 m3 Attention Civil Engineering (CE) Students!
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In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer?
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In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer?.
In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer?.
Solutions for In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer?, a detailed solution for In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a city, the chemical formula of biodegradable fraction of municipal solid waste (MSW) is C100H250O80N. The waste has to be treated by forced-aeration composting process for which air requirement has to be estimated.Assume oxygen in air (by weight) = 23% and density of air = 1.3 kg/m3. Atomic mass:C = 12, H = 1, O = 16, N = 14.C and H are oxidized completely whereas N is converted only into NH3 during oxidation.For oxidative degradation of 1 tonne of the waste, the required theoretical volume of air (in m3/tonne) will be (round off the nearest integer)a)1092b)4749c)1418d)8025Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
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