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The maximum dry density of a soil sample by the compaction test is 1.65 gm/l at an optimum moisture content of 20 percent Find the theoretical maximum dry density of the sample if the specific gravity of soil solids is 2.6 ?
Ans is 1.71 gm/l?
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The maximum dry density of a soil sample by the compaction test is 1.6...
Calculation of Theoretical Maximum Dry Density


Given:


  • Maximum dry density (𝜌d,max) = 1.65 gm/l

  • Optimum moisture content (OMC) = 20%

  • Specific gravity of soil solids (Gs) = 2.6



To find: Theoretical maximum dry density (𝜌d,max)


Formula used:

𝜌d,max = (Gs × γw) / (1 + e)

where, γw = unit weight of water = 1 gm/l

e = void ratio


Solution:

Given maximum dry density (𝜌d,max) = 1.65 gm/l

Given optimum moisture content (OMC) = 20%

Given specific gravity of soil solids (Gs) = 2.6


Let us assume that the soil sample is fully saturated i.e., e = 1


Substituting the given values in the formula:

𝜌d,max = (2.6 × 1) / (1 + 1) = 1.3 / 2 = 0.65 gm/l


Now, we know that the maximum dry density (𝜌d,max) occurs at the minimum void ratio (emin).


From the compaction test, we know that the maximum dry density (𝜌d,max) occurs at 20% moisture content. Hence, we can assume that the void ratio at this moisture content is the minimum void ratio (emin).


Let us assume that the void ratio at 20% moisture content is e = 0.8


Substituting the given values in the formula:

𝜌d,max = (2.6 × 1) / (1 + 0.8) = 2.6 / 1.8 = 1.44 gm/l


Therefore, the theoretical maximum dry density (𝜌d,max) of the soil sample is 1.44 gm/l.
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The maximum dry density of a soil sample by the compaction test is 1.65 gm/l at an optimum moisture content of 20 percent Find the theoretical maximum dry density of the sample if the specific gravity of soil solids is 2.6 ?Ans is 1.71 gm/l?
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