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The number of solutions of the simultaneous algebraic equations y = 3x + 3 and y = 3x + 5 is:
Correct answer is '0'. Can you explain this answer?
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The number of solutions of the simultaneous algebraic equations y = 3x...
System of equations,
⇒ a1x+b1y = c1
⇒ a2x+b2y = c2
For unique solution,
For Infinite solution,
For no solution,
Now,
⇒3x − y = −3
⇒ 3x − y = −5
⇒ a1 = 3,b1 = −1 and c1 = −3
⇒ a2 = 3,b2 = −1 and c2 = −5
So, this shows that the number of solutions for given simultaneous algebraic equations is 0.
Hence, the correct answer is 0.
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The number of solutions of the simultaneous algebraic equations y = 3x + 3 and y = 3x + 5 is:Correct answer is '0'. Can you explain this answer?
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