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A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:
Correct answer is '0.026'. Can you explain this answer?
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Most Upvoted Answer
A box contains 100 round discs, 50 square - shaped discs and 30 triang...
Given,
A box contains 100 round discs, 50 square-shaped discs and 30 triangular discs.
Probability 
Total number of discs = 180
Total number of triangular discs = 30
The probability that in first pass a triangular disc is attracted = 30/180
= 1/6
The first disc is kept aside and one square disc is kept inside.
The probability that in second pass a triangular disc is attracted
= 29/180
= 29/180
Required Probability =1/6 × 29/180
= 29/1080
= 0.026
Hence, the correct answer is 0.026.
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Community Answer
A box contains 100 round discs, 50 square - shaped discs and 30 triang...
Understanding the Problem
The box contains three types of discs:
- 100 round discs
- 50 square-shaped discs
- 30 triangular discs
Total discs = 100 + 50 + 30 = 180 discs.
Calculating the Probability
The probability of attracting a triangular disc during the first pass:
- There are 30 triangular discs out of 180 total discs.
- Probability (First pass) = Number of triangular discs / Total discs = 30 / 180 = 1 / 6.
After the first pass, one triangular disc is removed, leaving:
- Remaining triangular discs = 29
- Total remaining discs = 180 - 1 + 1 (since a square disc is added back) = 180.
Now, the probability of attracting a triangular disc during the second pass:
- Probability (Second pass) = Remaining triangular discs / New total = 29 / 180.
Calculating the Combined Probability
To find the probability of both events occurring (attracting a triangular disc in both passes):
- Combined Probability = Probability (First pass) × Probability (Second pass)
= (1/6) × (29/180)
Final Calculation
Calculating the combined probability:
- Combined Probability = (1/6) × (29/180) = 29 / 1080.
To convert this into decimal form:
- 29 / 1080 ≈ 0.02685, which rounds to approximately 0.026.
Conclusion
The probability of attracting a triangular disc both times is approximately 0.026, confirming the correctness of the provided answer.
The box contains three types of discs:
- 100 round discs
- 50 square-shaped discs
- 30 triangular discs
Total discs = 100 + 50 + 30 = 180 discs.
Calculating the Probability
The probability of attracting a triangular disc during the first pass:
- There are 30 triangular discs out of 180 total discs.
- Probability (First pass) = Number of triangular discs / Total discs = 30 / 180 = 1 / 6.
After the first pass, one triangular disc is removed, leaving:
- Remaining triangular discs = 29
- Total remaining discs = 180 - 1 + 1 (since a square disc is added back) = 180.
Now, the probability of attracting a triangular disc during the second pass:
- Probability (Second pass) = Remaining triangular discs / New total = 29 / 180.
Calculating the Combined Probability
To find the probability of both events occurring (attracting a triangular disc in both passes):
- Combined Probability = Probability (First pass) × Probability (Second pass)
= (1/6) × (29/180)
Final Calculation
Calculating the combined probability:
- Combined Probability = (1/6) × (29/180) = 29 / 1080.
To convert this into decimal form:
- 29 / 1080 ≈ 0.02685, which rounds to approximately 0.026.
Conclusion
The probability of attracting a triangular disc both times is approximately 0.026, confirming the correctness of the provided answer.
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A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer?
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A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer?.
A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer?.
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A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer?, a detailed solution for A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? has been provided alongside types of A box contains 100 round discs, 50 square - shaped discs and 30 triangular discs. All the discs are made up of iron and have an equal probability of getting attracted by a magnet. If a magnet which can attract only one disc in one pass and the disc is passed over them twice. What is the probability that both times a triangular disc is attracted? The disc attracted in one pass does not fall into box again, however each time a square shaped disc is kept into the box:Correct answer is '0.026'. Can you explain this answer? theory, EduRev gives you an
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