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The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, are
- a)1000, 100
- b)128, 13
- c)288, 29
- d)144, 15
Correct answer is option 'C'. Can you explain this answer?
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The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V ...
Question:
The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15.
Which option is correct?
Answer:
Given data:
Voltage ratio = 5000/500 V
Flux in the core = 7.82 mWb
Calculations:
The voltage ratio of a transformer is given by the formula:
V1/V2 = N1/N2
Where,
V1 = Primary voltage
V2 = Secondary voltage
N1 = Number of turns in primary coil
N2 = Number of turns in secondary coil
Given,
V1/V2 = 5000/500
So, N1/N2 = 5000/500
N1/N2 = 10
Also, the flux in the core is given by the formula:
Φ = (4.44 f N Φmax) / 10^6
Where,
f = Frequency = 50 Hz
N = Number of turns in the coil
Φmax = Maximum flux in the core
Given,
f = 50 Hz
Φmax = 7.82 mWb
So, we can find N as follows:
N = (Φ * 10^6) / (4.44 f Φmax)
N = (7.82 * 10^-3 * 10^6) / (4.44 * 50)
N = 288.28
Therefore, the number of turns in primary and secondary windings respectively are 288 and 29.
Hence, the correct option is C) 288, 29.
The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15.
Which option is correct?
Answer:
Given data:
Voltage ratio = 5000/500 V
Flux in the core = 7.82 mWb
Calculations:
The voltage ratio of a transformer is given by the formula:
V1/V2 = N1/N2
Where,
V1 = Primary voltage
V2 = Secondary voltage
N1 = Number of turns in primary coil
N2 = Number of turns in secondary coil
Given,
V1/V2 = 5000/500
So, N1/N2 = 5000/500
N1/N2 = 10
Also, the flux in the core is given by the formula:
Φ = (4.44 f N Φmax) / 10^6
Where,
f = Frequency = 50 Hz
N = Number of turns in the coil
Φmax = Maximum flux in the core
Given,
f = 50 Hz
Φmax = 7.82 mWb
So, we can find N as follows:
N = (Φ * 10^6) / (4.44 f Φmax)
N = (7.82 * 10^-3 * 10^6) / (4.44 * 50)
N = 288.28
Therefore, the number of turns in primary and secondary windings respectively are 288 and 29.
Hence, the correct option is C) 288, 29.
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The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer?.
The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The voltage ratio of a single-phase, 50 Hz transformer is 5000/500 V at no-load. The maximum value of the flux in the core is 7.82 mWb. The number of turns in primary and secondary windings respectively, area)1000, 100b)128, 13c)288, 29d)144, 15Correct answer is option 'C'. Can you explain this answer?.
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