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Kishenkant walks 10 kilometres towards North. From there, he walks 6 kilometres towards south. Then, he walks 3 kilometres towards east. How far and in which direction is he with reference to his starting point?
  • a)
    5 kilometres, west direction
  • b)
    5 kilometres, North-East Direction
  • c)
    7 kilometres, East Direction
  • d)
    7 kilometres, West Direction
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Kishenkant walks 10 kilometres towards North. From there, he walks 6 ...
Given Information:
- Kishenkant walks 10 kilometres towards North.
- From there, he walks 6 kilometres towards south.
- Then, he walks 3 kilometres towards east.

To Find:
- How far and in which direction is he with reference to his starting point?

Solution:

Step 1: Visualize the movements of Kishenkant

- Kishenkant starts at a point and walks 10 kilometres towards the North.
- From there, he walks 6 kilometres towards the South.
- Then, he walks 3 kilometres towards the East.

Step 2: Analyze the movements

- Kishenkant walks 10 kilometres towards the North.
- This means he moves 10 kilometres directly above his starting point.
- Then, he walks 6 kilometres towards the South.
- This means he moves 6 kilometres directly below his current position.
- Finally, he walks 3 kilometres towards the East.
- This means he moves 3 kilometres to the right of his current position.

Step 3: Calculate the final position

- From the above analysis, we can see that Kishenkant has moved 10 kilometres up and 6 kilometres down. The net displacement in the North direction is 10 - 6 = 4 kilometres.
- Additionally, he has moved 3 kilometres to the right in the East direction.

Step 4: Determine the distance and direction

- The distance is calculated using the Pythagorean theorem, which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.
- In this case, the hypotenuse represents the net displacement of Kishenkant, which is the distance from his starting point.
- The two sides are the North and East displacements, which are 4 kilometres and 3 kilometres respectively.
- Using the Pythagorean theorem, the distance is √(4^2 + 3^2) = √(16 + 9) = √25 = 5 kilometres.

- The direction can be determined by identifying the angle between the net displacement vector and the North direction.
- The angle can be calculated using the tangent function, which is the ratio of the opposite side (East displacement) to the adjacent side (North displacement).
- The angle is tan^(-1)(3/4) = 36.87 degrees.
- Therefore, the direction is North-East.

Step 5: Final answer

- Kishenkant is 5 kilometres away from his starting point in the North-East direction.
Free Test
Community Answer
Kishenkant walks 10 kilometres towards North. From there, he walks 6 ...
The movements of Kishenkant are as shown in figure
A to B, B to C and C to D
AC = (AB - BC) = (10 - 6) km = 4 km
Clearly, D is to the North-East of A .
Kishenkant's distance from starting point A
So, Kishenkant is 5 km to the North-East of his starting point
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Kishenkant walks 10 kilometres towards North. From there, he walks 6 kilometres towards south. Then, he walks 3 kilometres towards east. How far and in which direction is he with reference to his starting point?a)5 kilometres, west directionb)5 kilometres, North-East Directionc)7 kilometres, East Directiond)7 kilometres, West DirectionCorrect answer is option 'B'. Can you explain this answer?
Question Description
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