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In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion is
- a)N 010 G 03 X 7.0 Y 2.0 LF
- b)N 010 G 02 X 7.0 Y 2.0 LF
- c)N 010 G 01 X 7.0 Y 2.0 LF
- d)N 010 G 00 X 7.0 Y 2.0 LF
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a numerical control machining operation, the tool has to be moved ...
Given:
Initial point: (5, 4)
Final point: (7, 2)
Center of the circular path: (5, 2)
To move the tool from the initial point to the final point along a circular path, we need to use G and M codes in numerical control machining.
Explanation:
G Codes:
G codes are used to command specific operations in numerical control machining. In this case, we need to choose the appropriate G code to specify the type of motion.
G00: Rapid positioning
G01: Linear interpolation (straight line motion)
G02: Circular interpolation (clockwise)
G03: Circular interpolation (counterclockwise)
Since we need to move the tool along a circular path from (5, 4) to (7, 2) with a center at (5, 2), we need to choose either G02 or G03.
M Codes:
M codes are used to command miscellaneous functions in numerical control machining. In this case, we don't need any specific M code, so we can omit it.
Correct G and M Codes:
Looking at the given options, option 'B' is the correct one:
N010 G02 X7.0 Y2.0 L
Explanation of the correct answer:
In option 'B', the G code is specified as G02, which represents circular interpolation in a clockwise direction. This is the correct G code to use since the circular path in this case is clockwise, as the tool needs to move from point (5, 4) to point (7, 2) along a circular path with a center at (5, 2).
The X and Y values are specified as X7.0 and Y2.0, which represent the final point coordinates. Since the tool needs to move to point (7, 2), these values are correct.
The L command specifies that the motion is to be performed in a straight line from the current position to the specified point.
Therefore, option 'B' is the correct choice for the G and M codes in this numerical control machining operation.
Initial point: (5, 4)
Final point: (7, 2)
Center of the circular path: (5, 2)
To move the tool from the initial point to the final point along a circular path, we need to use G and M codes in numerical control machining.
Explanation:
G Codes:
G codes are used to command specific operations in numerical control machining. In this case, we need to choose the appropriate G code to specify the type of motion.
G00: Rapid positioning
G01: Linear interpolation (straight line motion)
G02: Circular interpolation (clockwise)
G03: Circular interpolation (counterclockwise)
Since we need to move the tool along a circular path from (5, 4) to (7, 2) with a center at (5, 2), we need to choose either G02 or G03.
M Codes:
M codes are used to command miscellaneous functions in numerical control machining. In this case, we don't need any specific M code, so we can omit it.
Correct G and M Codes:
Looking at the given options, option 'B' is the correct one:
N010 G02 X7.0 Y2.0 L
Explanation of the correct answer:
In option 'B', the G code is specified as G02, which represents circular interpolation in a clockwise direction. This is the correct G code to use since the circular path in this case is clockwise, as the tool needs to move from point (5, 4) to point (7, 2) along a circular path with a center at (5, 2).
The X and Y values are specified as X7.0 and Y2.0, which represent the final point coordinates. Since the tool needs to move to point (7, 2), these values are correct.
The L command specifies that the motion is to be performed in a straight line from the current position to the specified point.
Therefore, option 'B' is the correct choice for the G and M codes in this numerical control machining operation.
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Community Answer
In a numerical control machining operation, the tool has to be moved ...
Based on given data, to produce arc from point (5,4) to point (7,2) with center (5,2), the tool has to move in the clockwise direction. Hence G02 is used.
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In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer?.
In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer?.
Solutions for In a numerical control machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5,4). The correct G and M code for this motion isa)N 010 G 03 X 7.0 Y 2.0 LFb)N 010 G 02 X 7.0 Y 2.0 LFc)N 010 G 01 X 7.0 Y 2.0 LFd)N 010 G 00 X 7.0 Y 2.0 LFCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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