JEE Exam  >  JEE Questions  >   When 20 g of naphthoic acid (C11H8O2) is dis... Start Learning for Free
When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is
(Round off up to 1 decimal place)
    Correct answer is '0.5'. Can you explain this answer?
    Most Upvoted Answer
    When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene...
    Molar mass of naphthoic acid (C11H8O2) = 172 g mol-1
    Explore Courses for JEE exam
    When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer?
    Question Description
    When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer?.
    Solutions for When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer?, a detailed solution for When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? has been provided alongside types of When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is(Round off up to 1 decimal place)Correct answer is '0.5'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev