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Two particles A and B of masses mm and 2m are connected through a rod of length l. The system lies on a smooth horizontal surface. An impulse of magnitude mv to the particle B is imparted through impact horizontally but perpendicular to the rod. The angular velocity of the rod just after impact is v / nl. Find 2n.
    Correct answer is '4'. Can you explain this answer?
    Most Upvoted Answer
    Two particles A and B of masses mm and 2m are connected through a rod...
    From momentum conservation, Velocity of B just after impact = v/2
    Angular velocity, ω = v / 2l
    So, n = 2
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    Two particles A and B of masses mm and 2m are connected through a rod of length l. The system lies on a smooth horizontal surface. An impulse of magnitude mv to the particle B is imparted through impact horizontally but perpendicular to the rod. The angular velocity of the rod just after impact is v / nl. Find 2n.Correct answer is '4'. Can you explain this answer?
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    Two particles A and B of masses mm and 2m are connected through a rod of length l. The system lies on a smooth horizontal surface. An impulse of magnitude mv to the particle B is imparted through impact horizontally but perpendicular to the rod. The angular velocity of the rod just after impact is v / nl. Find 2n.Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two particles A and B of masses mm and 2m are connected through a rod of length l. The system lies on a smooth horizontal surface. An impulse of magnitude mv to the particle B is imparted through impact horizontally but perpendicular to the rod. The angular velocity of the rod just after impact is v / nl. Find 2n.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two particles A and B of masses mm and 2m are connected through a rod of length l. The system lies on a smooth horizontal surface. An impulse of magnitude mv to the particle B is imparted through impact horizontally but perpendicular to the rod. The angular velocity of the rod just after impact is v / nl. Find 2n.Correct answer is '4'. Can you explain this answer?.
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