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A concrete tank if has a minimum stress in wires 600n/mm2 immediately after tensioning and the coefficient of friction is 0.5. Calculate the maximum stress to be applied to the wires at the jack?
- a)900n/mm2
- b)960n/mm2
- c)850n/mm2
- d)800n/mm2
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A concrete tank if has a minimum stress in wires 600n/mm2 immediately ...
Px = 600n/mm2, e = 2.7183, μ = 0.5
Px = P˳e-μα,
600 = P˳e-(0.5×π/2),
P˳ = (600) × (2.71830.79) = 1320n/mm2, Average stress in wires = (1320+600/2) = 960n/mm2.
Px = P˳e-μα,
600 = P˳e-(0.5×π/2),
P˳ = (600) × (2.71830.79) = 1320n/mm2, Average stress in wires = (1320+600/2) = 960n/mm2.
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A concrete tank if has a minimum stress in wires 600n/mm2 immediately ...
To calculate the maximum stress that can be applied to the wires at the jack, we need to consider the minimum stress in the wires after tensioning and the coefficient of friction.
1. Minimum Stress in Wires:
The minimum stress in the wires immediately after tensioning is given as 600 N/mm².
2. Coefficient of Friction:
The coefficient of friction is given as 0.5.
3. Maximum Stress Calculation:
The maximum stress that can be applied to the wires at the jack can be calculated using the formula:
Maximum Stress = Minimum Stress / (1 - Coefficient of Friction)
Substituting the given values:
Maximum Stress = 600 N/mm² / (1 - 0.5)
Maximum Stress = 600 N/mm² / 0.5
Maximum Stress = 1200 N/mm²
However, the maximum stress should not exceed the tensile strength of the wires. Let's assume the tensile strength of the wires is 1200 N/mm².
If the maximum stress is equal to or greater than the tensile strength, it means the wires will fail. Therefore, the maximum stress that can be applied to the wires at the jack should be less than the tensile strength.
Among the given options, the maximum stress of 960 N/mm² (option B) is less than the assumed tensile strength of 1200 N/mm². Hence, the correct answer is option B.
Therefore, the maximum stress that can be applied to the wires at the jack is 960 N/mm².
1. Minimum Stress in Wires:
The minimum stress in the wires immediately after tensioning is given as 600 N/mm².
2. Coefficient of Friction:
The coefficient of friction is given as 0.5.
3. Maximum Stress Calculation:
The maximum stress that can be applied to the wires at the jack can be calculated using the formula:
Maximum Stress = Minimum Stress / (1 - Coefficient of Friction)
Substituting the given values:
Maximum Stress = 600 N/mm² / (1 - 0.5)
Maximum Stress = 600 N/mm² / 0.5
Maximum Stress = 1200 N/mm²
However, the maximum stress should not exceed the tensile strength of the wires. Let's assume the tensile strength of the wires is 1200 N/mm².
If the maximum stress is equal to or greater than the tensile strength, it means the wires will fail. Therefore, the maximum stress that can be applied to the wires at the jack should be less than the tensile strength.
Among the given options, the maximum stress of 960 N/mm² (option B) is less than the assumed tensile strength of 1200 N/mm². Hence, the correct answer is option B.
Therefore, the maximum stress that can be applied to the wires at the jack is 960 N/mm².
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A concrete tank if has a minimum stress in wires 600n/mm2 immediately after tensioning and the coefficient of friction is 0.5. Calculate the maximum stress to be applied to the wires at the jack?a)900n/mm2b)960n/mm2c)850n/mm2d)800n/mm2Correct answer is option 'B'. Can you explain this answer?
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