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A uniform bar of length 6a and mass 8m lies on a smooth horizontal table. Two point masses m and 2m moving in the same horizontal plane with speed 2 v and v, respectively, strike the bar [as shown in the figure] and stick to the bar after collision. Denoting angular velocity (about the centre of mass), total energy and centre of mass velocity respectively by ω, E and vc, we have after collision:
  • a)
    vc = 0
  • b)
    ω = 3v/5a
  • c)
    ω = v/5a
  • d)
    E = 3/5 mv2
Correct answer is option 'A,C,D'. Can you explain this answer?
Most Upvoted Answer
A uniform bar of length 6a and mass 8m lies on a smooth horizontal ta...
Using conservation of linear momentum. we have
Initial momentum = Final momentum
pi = mi(2v) - 2m(v) = ⇒ 0 pf = 0 hence velocity of the centre of mass of the combined system after collision is zero.
Vcm = 0
Using conservation of the angular momentum. we have
Initial angular momentum = Final angular momentum
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A uniform bar of length 6a and mass 8m lies on a smooth horizontal table. Two point masses m and 2m moving in the same horizontal plane with speed 2 v and v, respectively, strike the bar [as shown in the figure] and stick to the bar after collision. Denoting angular velocity (about the centre of mass), total energy and centre of mass velocity respectively by ω, E and vc, we have after collision:a)vc = 0b)ω = 3v/5ac)ω = v/5ad)E = 3/5 mv2Correct answer is option 'A,C,D'. Can you explain this answer?
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A uniform bar of length 6a and mass 8m lies on a smooth horizontal table. Two point masses m and 2m moving in the same horizontal plane with speed 2 v and v, respectively, strike the bar [as shown in the figure] and stick to the bar after collision. Denoting angular velocity (about the centre of mass), total energy and centre of mass velocity respectively by ω, E and vc, we have after collision:a)vc = 0b)ω = 3v/5ac)ω = v/5ad)E = 3/5 mv2Correct answer is option 'A,C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A uniform bar of length 6a and mass 8m lies on a smooth horizontal table. Two point masses m and 2m moving in the same horizontal plane with speed 2 v and v, respectively, strike the bar [as shown in the figure] and stick to the bar after collision. Denoting angular velocity (about the centre of mass), total energy and centre of mass velocity respectively by ω, E and vc, we have after collision:a)vc = 0b)ω = 3v/5ac)ω = v/5ad)E = 3/5 mv2Correct answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform bar of length 6a and mass 8m lies on a smooth horizontal table. Two point masses m and 2m moving in the same horizontal plane with speed 2 v and v, respectively, strike the bar [as shown in the figure] and stick to the bar after collision. Denoting angular velocity (about the centre of mass), total energy and centre of mass velocity respectively by ω, E and vc, we have after collision:a)vc = 0b)ω = 3v/5ac)ω = v/5ad)E = 3/5 mv2Correct answer is option 'A,C,D'. Can you explain this answer?.
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