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Read the following information carefully and answer the questions based on it.
Four surfaces- a cube, a cuboid, a cylinder and a sphere are in consideration. The length of the cube is (2x-8) cm while its lateral surface area is 4(yz-4y) sq cm. The length and breadth of the cuboid is (x+y) cm and (y+z) cm respectively. Volume of the cuboid is (5xyz-688) cubic cm. The radius of the cylinder is x cm and its height is (z-3) cm. If it’s dimensions were reversed, the volume of the cylinder will become 3/2 times of its original volume. The radius of the sphere is (y+1) cm. If it was melted into smaller spheres of radius (x/2) cm, the number of spheres that would be formed is 27. The radius of both the smaller and larger spheres is more than 5 cm.
Q. What is the length of the rod of maximum length that can be inserted into the cube without disturbing its dimensions?
  • a)
    20√3 cm
  • b)
    24√3 cm
  • c)
    18√3 cm
  • d)
    15√3 cm
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Read the following information carefully and answer the questions bas...
Length of the cube = 2x - 8
⇒ Lateral surface area of the cube = 4a2 = 4(2x - 8)2 = 4(4x2 + 64 - 32x)
⇒ 4(4x2 + 64 - 32x) = 4y (z - 4) ---------- (1)
Radius of cylinder = x
Height of cylinder = (z - 3)
Volume of the cylinder = π * x2 *(z - 3)
If the dimensions were reversed = π*(z - 3)2*x
Thus, π*(z - 3)2*x = 3/2* π*x2*(z - 3)
⇒ z - 3 = 3/2*x
⇒ z = (3x/2) + 3
Now, radius of sphere = y + 1 cm
Volume of sphere = 4π/3*(y + 1)3
Radius of smaller sphere = x/2
Volume of smaller sphere = 4π/3*(x/2)3
⇒ 4π/3*(y + 1)3 = 27*4 π/3*(x/2)3
⇒ y + 1 = 3(x/2) = 3x/2
⇒ y = (3x/2) -1
From equation (1) we get
4(4x2 + 64-32x) = 4y (z - 4) = 4(3x/2 - 1)(3x/2 + 3 - 4) = (3x - 2)2
⇒ 16x2 + 256 - 128x = 9x2 + 4 - 12x
⇒ 7x2 - 116x + 252 = 0
⇒ (x - 14)(7x - 18) = 0
⇒ x = 14 or x = 18/7
So, z = 3x/2+3 = 24 or 48/7
And, y = 3x/2-1 = 20 or 20/7. But y + 1 = 27/7< />
Thus, y = 20, x = 14 and z = 24
Now, length of cuboid = x + y = 14 + 20 = 34 cm
Breadth of cuboid = y + z = 20 + 24 = 44 cm
Volume of cuboid = 5xyz - 688 = 5*14*20*24 - 688 = 32912 cubic cm
Height of cuboid = 32912/34/44 = 22cm
Thus,
For cube, edge = 2x - 8 = 2*14 - 8 = 20 cm
For cuboid, length = 34 cm, breadth = 44 cm, heigh t= 22 cm
For cylinder, radius=14 cm, height = 24 - 3 = 21 cm
For smaller sphere, radius = 7 cm
For larger sphere, radius = 21 cm
Length of rod of maximum length that can be inserted = √3*edge length = 20√3 cm
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Read the following information carefully and answer the questions based on it.Four surfaces- a cube, a cuboid, a cylinder and a sphere are in consideration. The length of the cube is (2x-8) cm while its lateral surface area is 4(yz-4y) sq cm. The length and breadth of the cuboid is (x+y) cm and (y+z) cm respectively. Volume of the cuboid is (5xyz-688) cubic cm. The radius of the cylinder is x cm and its height is (z-3) cm. If it’s dimensions were reversed, the volume of the cylinder will become 3/2 times of its original volume. The radius of the sphere is (y+1) cm. If it was melted into smaller spheres of radius (x/2) cm, the number of spheres that would be formed is 27. The radius of both the smaller and larger spheres is more than 5 cm.Q. What is the length of the rod of maximum length that can be inserted into the cube without disturbing its dimensions?a)20√3 cmb)24√3 cmc)18√3 cmd)15√3 cme)None of theseCorrect answer is option 'A'. Can you explain this answer?
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