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The number of sleepers saved by adopting the minimum density for constructing a broad gauge railway track of 1856 m log in India is ____________. (Answer up to the nearest integer)
    Correct answer is '435'. Can you explain this answer?
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    The number of sleepers saved by adopting the minimum density for cons...
    Number of rails required for broad gauge track = 1856/12.8 = 145
    Maximum number of sleepers per rail = 12.8 + 6 = 18.8 ≈ 19
    Minimum numbers of sleepers per rail = 12.8 + 3 = 15.8 ≈ 16
    Savings of sleepers = 19(145) – 16(145) = 3(145) = 435 sleepers
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    The number of sleepers saved by adopting the minimum density for constructing a broad gauge railway track of 1856 m log in India is ____________. (Answer up to the nearest integer)Correct answer is '435'. Can you explain this answer?
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    The number of sleepers saved by adopting the minimum density for constructing a broad gauge railway track of 1856 m log in India is ____________. (Answer up to the nearest integer)Correct answer is '435'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The number of sleepers saved by adopting the minimum density for constructing a broad gauge railway track of 1856 m log in India is ____________. (Answer up to the nearest integer)Correct answer is '435'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of sleepers saved by adopting the minimum density for constructing a broad gauge railway track of 1856 m log in India is ____________. (Answer up to the nearest integer)Correct answer is '435'. Can you explain this answer?.
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