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Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer?.

Solutions for Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer?, a detailed solution for Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? has been provided alongside types of Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Directions: The answer to the following question is a single-digit integer, ranging from 0 to 9.Let p(x) be a real polynomial of least degree, which has a local maxima at x = -4 and a local minimum at x = 9. If p(0) = 0 and p(-6) = 108, then what is the value of p'(-4)?Correct answer is '0'. Can you explain this answer? tests, examples and also practice JEE tests.