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Directions: The answer to the following question is a single digit integer ranging from 0 to 9.
The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 is
    Correct answer is '4'. Can you explain this answer?
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    Directions: The answer to the following question is a single digit in...
    Let α,β be the roots of given quadratic equation. Then,
    Let H be the harmonic mean between α and β, then
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    Directions: The answer to the following question is a single digit integer ranging from 0 to 9.The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 isCorrect answer is '4'. Can you explain this answer?
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    Directions: The answer to the following question is a single digit integer ranging from 0 to 9.The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 isCorrect answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Directions: The answer to the following question is a single digit integer ranging from 0 to 9.The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 isCorrect answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: The answer to the following question is a single digit integer ranging from 0 to 9.The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 isCorrect answer is '4'. Can you explain this answer?.
    Solutions for Directions: The answer to the following question is a single digit integer ranging from 0 to 9.The harmonic mean of the roots of the equation (5 + √2) x2 - (4 + √5) x + 8 + 2√5 = 0 isCorrect answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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