JEE Exam  >  JEE Questions  >   Observe the following figure carefully, whic... Start Learning for Free
Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.
If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?
Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.
Neglect any volume of solid produced and connecting tube.
Assume that the manometer is sufficiently long and thin.
    Correct answer is '8'. Can you explain this answer?
    Most Upvoted Answer
    Observe the following figure carefully, which is showing the initial ...
    Remaining moles of NH3 = 5
    Pressure of NH3 in first and second container will be same
    Pressure in container containing He = 1 atm
    ∴ pdiff. = 1.5 atm
    hHgdHg = hglydgly
    =
    ∴ x = 8
    Explore Courses for JEE exam
    Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer?
    Question Description
    Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer?.
    Solutions for Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer?, a detailed solution for Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? has been provided alongside types of Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Observe the following figure carefully, which is showing the initial conditions of the systems when all valves are closed.If at 0°C all valves are opened and system is allowed to come at equilibrium, then calculate the height difference in the glycerine levels of the U tube manometer in (cm) and write the answer as 95x cm. What is value of x ?Assuming the complete reaction of NH3(g) + HCl(g) ⟶ NH4Cl(s)NH3g + HClg ⟶ NH4Cls.Neglect any volume of solid produced and connecting tube.Assume that the manometer is sufficiently long and thin.Correct answer is '8'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev