Solution:

Given, A is a 3-rowed square matrix such that |A| = 2.

To find: |adj(adj(adj A2))|

Let's first calculate A2.

A2 = A.A

Now, A has determinant |A| = 2. So,

|A2| = |A.A| = |A|.|A| = 22 = 4

Next, let's calculate adj A2.

adj A2 = (A2)-1.adj(A2)

Here, (A2)-1 is the inverse of A2.

To calculate adj(A2), we need to calculate the cofactor matrix of A2 and then take its transpose.

Cofactor matrix of A2 can be calculated as follows:

C11 = (-1)1+1.det(M11) = det(M11) = a22.a33 - a23.a32
C12 = (-1)1+2.det(M12) = -det(M12) = -(a21.a33 - a23.a31)
C13 = (-1)1+3.det(M13) = det(M13) = a21.a32 - a22.a31
C21 = (-1)2+1.det(M21) = -det(M21) = -(a12.a33 - a13.a32)
C22 = (-1)2+2.det(M22) = det(M22) = a11.a33 - a13.a31
C23 = (-1)2+3.det(M23) = -det(M23) = -(a11.a32 - a12.a31)
C31 = (-1)3+1.det(M31) = det(M31) = a12.a23 - a13.a22
C32 = (-1)3+2.det(M32) = -det(M32) = -(a11.a23 - a13.a21)
C33 = (-1)3+3.det(M33) = det(M33) = a11.a22 - a12.a21

Where Mij is the matrix obtained by removing the ith row and jth column of A2.

Using the above formula, we can calculate the cofactor matrix of A2 as follows:

C11 = (4.6 - 5.7) = -2
C12 = -(4.3 - 5.6) = 2
C13 = (4.2 - 5.4) = -1
C21 = -(3.6 - 5.9) = 6
C22 = (3.3 - 5.9) = -2
C23 = -(3.2 - 4.9) = 3
C31 = (2.7 - 4.8) = -2
C32 = -(2.3 - 4.8) = 2
C33 = (2.2 - 4.6) = -2

So, the cofactor matrix of A2 is:

C2 = [-2 2 -1; 6 -2 3; -2 2 -2]

Taking the transpose of C2, we get adj(A2) as:

adj(A2) = [-2 6 -2; 2 -2 2; -1 3 -2]

Next, let's calculate (A2)-

Let B = adj(adjA²), then B is also 3 by 3 matrix