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The sight distance, if the coefficient of friction is 0.25, is 550 m. Find the velocity(in m/s). (Answer up to the nearest integer)
    Correct answer is '166'. Can you explain this answer?
    Most Upvoted Answer
    The sight distance, if the coefficient of friction is 0.25, is 550 m. ...
    Given: f = 0.25 and S = 550 m
    Velocity V is given by
    S = 0.7 V + V2/254f
    550 = 0.7 V + V2/254(0.25)
    V = 166 m/s
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    Community Answer
    The sight distance, if the coefficient of friction is 0.25, is 550 m. ...
    The Sight Distance and Velocity

    To calculate the velocity, we need to understand the concept of sight distance and its relationship with the coefficient of friction.

    Understanding Sight Distance
    Sight distance refers to the maximum distance a driver can see ahead on a roadway, allowing them to safely react to any potential hazards or obstacles. It is crucial for ensuring safe driving conditions.

    Relationship with Coefficient of Friction
    The coefficient of friction plays a vital role in determining the sight distance. It represents the frictional resistance between a vehicle's tires and the road surface. A higher coefficient of friction allows for greater deceleration and shorter stopping distances.

    Calculating Sight Distance
    The formula to calculate the sight distance is as follows:

    Sight Distance = (Velocity^2) / (2 * Coefficient of Friction * g)

    Where:
    - Velocity represents the speed of the vehicle in meters per second (m/s)
    - Coefficient of Friction is the frictional resistance between the tires and the road surface
    - g is the acceleration due to gravity (approximately 9.8 m/s^2)

    Given Information
    - Coefficient of Friction = 0.25
    - Sight Distance = 550 m

    Calculating Velocity
    We can rearrange the formula to solve for velocity:

    Velocity = √(2 * Coefficient of Friction * g * Sight Distance)

    Substituting the given values:

    Velocity = √(2 * 0.25 * 9.8 * 550)
    Velocity = √(2695)
    Velocity ≈ 51.92 m/s

    Rounding the answer to the nearest integer, the velocity is approximately 52 m/s.

    However, the given correct answer is '166'. It is possible that there is a mistake in the question or the answer provided.
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    The sight distance, if the coefficient of friction is 0.25, is 550 m. Find the velocity(in m/s). (Answer up to the nearest integer)Correct answer is '166'. Can you explain this answer?
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