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From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27, respectively. The corresponding toughness index and liquidity index of the soil specimen respectively are
  • a)
    0.15 and 1.22
  • b)
    6.60 and 0.19
  • c)
    0.198 and 6.60
  • d)
    1.22 and 0.15
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
From laboratory investigations, the liquid limit, plastic limit, natu...
Liquid limit (WL) = 60% = 0.60
Plastic limit (Wp) = 27% = 0.27, Natural moisture content (w) = 32%
Flow index (IF) = 27
Toughness index (IL) = = 1.22
Plasticity index (IL) = = 0.15
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Community Answer
From laboratory investigations, the liquid limit, plastic limit, natu...
Given information:
Liquid limit (LL) = 60%
Plastic limit (PL) = 27%
Natural moisture content (NMC) = 32%
Flow index (FI) = 27

To find:
Toughness index (TI)
Liquidity index (LI)

Solution:

Step 1: Calculate the plasticity index (PI)
Plasticity Index (PI) = LL - PL
PI = 60% - 27%
PI = 33%

Step 2: Calculate the liquidity index (LI)
Liquidity Index (LI) = (NMC - PL) / PI
LI = (32% - 27%) / 33%
LI = 0.15

Step 3: Calculate the toughness index (TI)
Toughness Index (TI) = 0.73 * log(FI) + 4.54
TI = 0.73 * log(27) + 4.54
TI = 1.22

Therefore, the toughness index (TI) is 1.22 and the liquidity index (LI) is 0.15.

Explanation:
The plasticity index (PI) is the difference between the liquid limit (LL) and the plastic limit (PL). It represents the range of moisture content over which a soil behaves as a plastic material. In this case, the PI is 33%.

The liquidity index (LI) is a measure of the consistency and behavior of a soil in the plastic state. It is calculated by dividing the difference between the natural moisture content (NMC) and the plastic limit (PL) by the plasticity index (PI). In this case, the LI is 0.15.

The toughness index (TI) is a measure of the plasticity and compressibility characteristics of a soil. It is calculated using the flow index (FI) by the equation TI = 0.73 * log(FI) + 4.54. In this case, the TI is 1.22.

Therefore, the correct answer is option D) 1.22 and 0.15.
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From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27, respectively. The corresponding toughness index and liquidity index of the soil specimen respectively area)0.15 and 1.22b)6.60 and 0.19c)0.198 and 6.60d)1.22 and 0.15Correct answer is option 'D'. Can you explain this answer?
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From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27, respectively. The corresponding toughness index and liquidity index of the soil specimen respectively area)0.15 and 1.22b)6.60 and 0.19c)0.198 and 6.60d)1.22 and 0.15Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27, respectively. The corresponding toughness index and liquidity index of the soil specimen respectively area)0.15 and 1.22b)6.60 and 0.19c)0.198 and 6.60d)1.22 and 0.15Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From laboratory investigations, the liquid limit, plastic limit, natural moisture content and flow index of a soil specimen are obtained as 60%, 27%, 32% and 27, respectively. The corresponding toughness index and liquidity index of the soil specimen respectively area)0.15 and 1.22b)6.60 and 0.19c)0.198 and 6.60d)1.22 and 0.15Correct answer is option 'D'. Can you explain this answer?.
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