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A point object is placed in front of a thin biconvex lens, of focal length 20 cm. When placed in air, the refractive index of material of lens is 1.5 The further surface of the lens is silvered and is having radius of curvature of 25 cm. The position of final image of object is at 25/x cm from lens. Determine the value of x?
    Correct answer is '2'. Can you explain this answer?
    Most Upvoted Answer
    A point object is placed in front of a thin biconvex lens, of focal l...
    Focal length of the lens

    Given: Focal length of the lens, f = 20 cm

    Refractive index of the lens material

    Given: Refractive index of the lens material, μ = 1.5

    Radius of curvature of the silvered surface

    Given: Radius of curvature of the silvered surface, R = 25 cm

    Position of the final image

    Given: The position of the final image of the object is at 25/x cm from the lens.

    Using the lens formula

    The lens formula relates the object distance (u), image distance (v), and focal length (f) of a lens, and can be given as:

    1/f = 1/v - 1/u

    In this case, the object distance (u) is not given, but we know that the point object is placed in front of the lens. For a thin lens, the object distance can be considered as negative (-u) when the object is placed on the same side as the incident light.

    Since the point object is placed in air, the refractive index of the medium surrounding the lens is 1. The refractive index of the lens material is given as 1.5. Using the lens formula, we can write:

    1/f = (μ - 1) * (1/R1 - 1/R2)

    Where R1 is the radius of curvature of the first surface of the lens and R2 is the radius of curvature of the second surface of the lens.

    Calculation

    In this case, since the lens is biconvex, both surfaces have the same radius of curvature.

    1/20 = (1.5 - 1) * (1/25 - 1/25)

    1/20 = 0.5 * (0 - 0)

    1/20 = 0

    This is not consistent, which means there is no real solution. Therefore, the given values for the focal length, refractive index, and radius of curvature must be incorrect.

    The correct answer cannot be determined based on the given information. Please check the values and provide accurate information to solve the problem.
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    Community Answer
    A point object is placed in front of a thin biconvex lens, of focal l...
    We know that a thin silvered lens is equivalent to a combination of two lenses and a mirror. This equation system is working as a mirror whose
    focal length is given by
    where, fL = 20 cm and fM = −25 / 2cm
    Let v is the image distance from lens, then
    ⇒ v = −12.5 cm
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    A point object is placed in front of a thin biconvex lens, of focal length 20 cm. When placed in air, the refractive index of material of lens is 1.5 The further surface of the lens is silvered and is having radius of curvature of 25 cm. The position of final image of object is at 25/x cm from lens. Determine the value of x?Correct answer is '2'. Can you explain this answer?
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    A point object is placed in front of a thin biconvex lens, of focal length 20 cm. When placed in air, the refractive index of material of lens is 1.5 The further surface of the lens is silvered and is having radius of curvature of 25 cm. The position of final image of object is at 25/x cm from lens. Determine the value of x?Correct answer is '2'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A point object is placed in front of a thin biconvex lens, of focal length 20 cm. When placed in air, the refractive index of material of lens is 1.5 The further surface of the lens is silvered and is having radius of curvature of 25 cm. The position of final image of object is at 25/x cm from lens. Determine the value of x?Correct answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point object is placed in front of a thin biconvex lens, of focal length 20 cm. When placed in air, the refractive index of material of lens is 1.5 The further surface of the lens is silvered and is having radius of curvature of 25 cm. The position of final image of object is at 25/x cm from lens. Determine the value of x?Correct answer is '2'. Can you explain this answer?.
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