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A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.
Correct answer is '60'. Can you explain this answer?
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A point object in air is in front of the curved surface of a plano-con...
Given information:
- Radius of curvature (R) = 30 cm
- Refractive index (n) = 1.5
Formula:
The formula to calculate the focal length (f) of a lens is:
\[\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)\]
Where:
- f = focal length of the lens
- n = refractive index of the lens material
- R1 = radius of curvature of the first surface
- R2 = radius of curvature of the second surface
Solution:
- Given that the lens is plano-convex, one of the surfaces is flat (R1 = ∞) and the other surface has a radius of curvature R = 30 cm.
- Since one of the radii of curvature is infinite, the formula simplifies to:
\[\frac{1}{f} = (n-1) \left( \frac{1}{R} \right)\]
Substitute the values:
\[\frac{1}{f} = (1.5-1) \left( \frac{1}{30} \right)\]
\[\frac{1}{f} = 0.5 \left( \frac{1}{30} \right)\]
\[\frac{1}{f} = \frac{1}{60}\]
Therefore, the focal length of the plano-convex lens is 60 cm.
- Radius of curvature (R) = 30 cm
- Refractive index (n) = 1.5
Formula:
The formula to calculate the focal length (f) of a lens is:
\[\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)\]
Where:
- f = focal length of the lens
- n = refractive index of the lens material
- R1 = radius of curvature of the first surface
- R2 = radius of curvature of the second surface
Solution:
- Given that the lens is plano-convex, one of the surfaces is flat (R1 = ∞) and the other surface has a radius of curvature R = 30 cm.
- Since one of the radii of curvature is infinite, the formula simplifies to:
\[\frac{1}{f} = (n-1) \left( \frac{1}{R} \right)\]
Substitute the values:
\[\frac{1}{f} = (1.5-1) \left( \frac{1}{30} \right)\]
\[\frac{1}{f} = 0.5 \left( \frac{1}{30} \right)\]
\[\frac{1}{f} = \frac{1}{60}\]
Therefore, the focal length of the plano-convex lens is 60 cm.
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A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer?
Question Description
A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer?.
A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer?.
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A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer?, a detailed solution for A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? has been provided alongside types of A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is 30 cm and the refractive index of the lens material is 1.5, then the focal length of the lens (in cm) is _______.Correct answer is '60'. Can you explain this answer? theory, EduRev gives you an
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