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As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer?.

Solutions for As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

Here you can find the meaning of As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice As per IS 456 2000, short axially loaded RC column members using mild steel are des by the equationwhere,Pu = factored axial load on the memberfck = characteristic compressive strength of the concretefy = characteristic strength of the compression reinforcementAg = gross cross sectional areaAc = area of concreteAsc = area of longitudinal reinforcement of columna)Pu = 0.4 fck Ac + 0.67 fyAscb)Pu = 0.25 fck Ac + 0.87 fyAscc)Pu = 0.4 fck Ac - 0.67 fyAscd)Pu = 0.25 fck Ac - 0.87 fyAscCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.