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Which of the following statement is not true about round-robin scheduling?
  • a)
     To implement RR scheduling, we keep the ready queue as a FIFO queue of processes.
  • b)
     If there are n processes in the ready queue and time quantum is q, then each process gets nq of the CPU time in chunks of atmost q time units.
  • c)
     Each process must wait for no longer than  (n−1)/q time units until its next time quantum.
  • d)
     If the time quantum is too large, then Round robin scheduling behaves like FCFS.
Correct answer is option 'A,D'. Can you explain this answer?
Most Upvoted Answer
Which of the following statement is not true about round-robin schedul...
C) Each process must wait for no longer than (n-1) time units before it gets its turn again.

In round-robin scheduling, each process is given a fixed time quantum to execute, and if it does not complete its execution within that time, it is moved to the end of the ready queue. Therefore, there is no guarantee that a process will get its turn again immediately after completing its execution. It may have to wait for a longer period of time depending on the number of processes in the ready queue and their execution times.
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Community Answer
Which of the following statement is not true about round-robin schedul...
We know that:
The round-robin scheduling algorithm is designed for time sharing systems. It is similar to FCFS but preemption is added to enable the system to switch between processes.
Now,
Some points about round- robin scheduling:
  • To implement round robin, we keep the queue as a FIFO queue of processes.
  • Round robin scheduling is preemptive.
  • If there are n processes in the ready queue and the time quantum is q, then each process gets 1/n of the CPU time in chunks of at most q time units. Each process must wait no longer than (n−1) × q time units until its next time quantum.
  • Performance of the round robin algorithm depends on the size of time quantum.
  • If time quantum is too large, then round robin behaves like FCFS.
  • If time quantum is too small, then this approach is called processor sharing.
Hence, the correct options are (A) and (D).
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Which of the following statement is not true about round-robin scheduling?a)To implement RR scheduling, we keep the ready queue as a FIFO queue of processes.b)If there are n processes in the ready queue and time quantum is q, then each process gets nq of the CPU time in chunks of atmost q time units.c)Each process must wait for no longer than(n−1)/q time units until its next time quantum.d)If the time quantum is too large, then Round robin scheduling behaves like FCFS.Correct answer is option 'A,D'. Can you explain this answer?
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