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A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)
- a)150.8 m
- b)127.6 m
- c)140.2 m
- d)100.5 m
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A bullet is fired upwards at an angle of 30° to the horizontal fro...
° to the horizontal with an initial velocity of 500 m/s. What is the maximum height reached by the bullet and how long does it take to reach that height?
We can use the following equations of motion to solve this problem:
Vertical motion:
h = v₀t + 1/2gt² (where h is the height, v₀ is the initial velocity in the vertical direction, g is the acceleration due to gravity, and t is the time)
Horizontal motion:
x = v₀x t (where x is the horizontal distance traveled, v₀x is the initial velocity in the horizontal direction, and t is the time)
First, we need to find the initial vertical velocity of the bullet. We can use trigonometry to find that:
v₀y = v₀sin(30°) = 250 m/s
Now we can find the time it takes for the bullet to reach its maximum height. At the maximum height, the vertical velocity is zero (since the bullet momentarily stops before falling back down). So we can use the following equation:
v = v₀y + gt
0 = 250 - 9.81t
t = 25.5 seconds
Now we can use the time to find the maximum height reached by the bullet:
h = v₀y t + 1/2gt²
h = 250(25.5) + 1/2(9.81)(25.5)²
h = 31891 meters
Therefore, the maximum height reached by the bullet is approximately 31891 meters, and it takes 25.5 seconds to reach that height.
We can use the following equations of motion to solve this problem:
Vertical motion:
h = v₀t + 1/2gt² (where h is the height, v₀ is the initial velocity in the vertical direction, g is the acceleration due to gravity, and t is the time)
Horizontal motion:
x = v₀x t (where x is the horizontal distance traveled, v₀x is the initial velocity in the horizontal direction, and t is the time)
First, we need to find the initial vertical velocity of the bullet. We can use trigonometry to find that:
v₀y = v₀sin(30°) = 250 m/s
Now we can find the time it takes for the bullet to reach its maximum height. At the maximum height, the vertical velocity is zero (since the bullet momentarily stops before falling back down). So we can use the following equation:
v = v₀y + gt
0 = 250 - 9.81t
t = 25.5 seconds
Now we can use the time to find the maximum height reached by the bullet:
h = v₀y t + 1/2gt²
h = 250(25.5) + 1/2(9.81)(25.5)²
h = 31891 meters
Therefore, the maximum height reached by the bullet is approximately 31891 meters, and it takes 25.5 seconds to reach that height.
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Community Answer
A bullet is fired upwards at an angle of 30° to the horizontal fro...
Projectile Motion:
- A projectile is any object that once thrown continues in motion by its own inertia.
- A projectile motion takes place under the influence of the force of gravity only.
Maximum of Projectile height:
- The maximum height of a projectile is the vertical distance at which the projectile reaches zero vertical velocity.
- It is given by the equation:
Range of projectile:
- The range of a projectile is the horizontal distance covered by the projectile during its motion. It is given by the equation:
Where u is the velocity with which the projectile is thrown, θ is the angle at which the projectile is thrown.
Calculation:
Given:
θ = 30°, u = 100 m/s
Calculation:
Given:
θ = 30°, u = 100 m/s
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A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer?
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A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer?.
A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer?.
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A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bullet is fired upwards at an angle of 30° to the horizontal from a point P on a hill, and it strikes a target which is 80 m lower than P. The initial velocity of the bullet is 100 m/s. Calculate the maximum height to which the bullet will rise above the horizontal. (Assume g = 9.81 m/s2)a)150.8 mb)127.6 mc)140.2 md)100.5 mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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