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The direction of projection for the range of a projectile to be maximum on an inclined plane having angle of inclination 30° to the horizontal should be
- a)30° with the horizontal
- b)30° with vertical
- c)45° with horizontal plane
- d)45° with inclined plane
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The direction of projection for the range of a projectile to be maximu...
The direction of projection for the range of a projectile to be maximum on an inclined plane with an angle of inclination of 30 degrees would be parallel to the inclined plane.
When the projectile is launched parallel to the inclined plane, the gravitational force acting on the projectile can be resolved into two components: one parallel to the inclined plane and one perpendicular to the inclined plane. The component parallel to the inclined plane does not affect the range of the projectile, while the component perpendicular to the inclined plane contributes to the vertical motion of the projectile.
By launching the projectile parallel to the inclined plane, the component of gravity perpendicular to the inclined plane is minimized, allowing the projectile to travel further along the inclined plane before hitting the ground. This maximizes the range of the projectile on the inclined plane.
When the projectile is launched parallel to the inclined plane, the gravitational force acting on the projectile can be resolved into two components: one parallel to the inclined plane and one perpendicular to the inclined plane. The component parallel to the inclined plane does not affect the range of the projectile, while the component perpendicular to the inclined plane contributes to the vertical motion of the projectile.
By launching the projectile parallel to the inclined plane, the component of gravity perpendicular to the inclined plane is minimized, allowing the projectile to travel further along the inclined plane before hitting the ground. This maximizes the range of the projectile on the inclined plane.
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The direction of projection for the range of a projectile to be maximu...
For the maximum range in case of the inclined plane, the angle from the inclined should be,
where, θ = angle of projection from the inclined plane and α is the angle of incline from horizontal.
Calculation:
Given:
The angle of incline, α = 30°
For maximum range,
θ = 30° with the inclined plane.
So, the angle of projection from the vertical = 90° - ( 30° + 30°) = 30°
where, θ = angle of projection from the inclined plane and α is the angle of incline from horizontal.
Calculation:
Given:
The angle of incline, α = 30°
For maximum range,
θ = 30° with the inclined plane.
So, the angle of projection from the vertical = 90° - ( 30° + 30°) = 30°
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The direction of projection for the range of a projectile to be maximum on an inclined plane having angle of inclination 30° to the horizontal should bea)30° with the horizontalb)30° with verticalc)45° with horizontal planed)45° with inclined planeCorrect answer is option 'B'. Can you explain this answer?
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