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The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) is
- a)β/2
- b)30º + β/2
- c)45º + β/2
- d)60º + β/2
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The range of projectile will be maximum for a given velocity of projec...
Launch angle) is 45 degrees with the horizontal. This is because at this angle, the horizontal and vertical components of the velocity are equal. The horizontal component of the velocity determines the range of the projectile, while the vertical component determines the height of the projectile. At angles greater than 45 degrees, the vertical component of the velocity becomes larger, causing the projectile to reach a greater height but decreasing its range. At angles less than 45 degrees, the horizontal component of the velocity becomes smaller, decreasing the range of the projectile.
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The range of projectile will be maximum for a given velocity of projectile, when the angle of projection (α) isa)β/2b)30º + β/2c)45º + β/2d)60º + β/2Correct answer is option 'C'. Can you explain this answer?
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