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A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer?.

Solutions for A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux.The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its centre at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the centre of the loop with its north pole always facing the loop, as shown in the figure below.The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is , where μ0is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is , where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles.Q. The work done in bringing the dipole from infinity to a distance r from the centre of the loop by the given process is proportional toa)m/r5b)m2/r5c)m2/r6d)m2/r7Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.